CAIE S1 2023 March — Question 5 3 marks

Exam BoardCAIE
ModuleS1 (Statistics 1)
Year2023
SessionMarch
Marks3
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicIndependent Events
TypeIndependence in combinatorial scenarios
DifficultyStandard +0.8 This question requires students to calculate P(A), P(B), and P(A∩B) for non-trivial events involving arrangements, then verify the independence condition P(A∩B) = P(A)P(B). Finding P(B) requires systematic counting of arrangements where red is left of both green and yellow, which is conceptually demanding. The multi-step reasoning and need to carefully enumerate cases makes this harder than standard independence questions.
Spec2.03a Mutually exclusive and independent events

Marco has four boxes labelled \(K\), \(L\), \(M\) and \(N\). He places them in a straight line in the order \(K\), \(L\), \(M\), \(N\) with \(K\) on the left. Marco also has four coloured marbles: one is red, one is green, one is white and one is yellow. He places a single marble in each box, at random. Events \(A\) and \(B\) are defined as follows. \(A\): The white marble is in either box \(L\) or box \(M\). \(B\): The red marble is to the left of both the green marble and the yellow marble. Determine whether or not events \(A\) and \(B\) are independent. [3]

Question 5:
AnswerMarks
5Where a candidate has misread a number in the question and used that value consistently throughout, provided that number does not alter the difficulty or
the method required, award all marks earned and deduct just 1 mark for the misread.
AnswerMarks
51 8 1
P(A) = , P(B) = = ,
AnswerMarks Guidance
2 24 3B1 Both stated, accept unsimplified.
1
P(AB) =
AnswerMarks Guidance
6M1 Evidence that independence properties not used.
1 1 1
P(A) × P(B) =  =
2 3 6
AnswerMarks Guidance
so events are independentA1 Evaluated and conclusion stated.
P(A) × P(B) and P(AB) seen.
3
AnswerMarks Guidance
QuestionAnswer Marks
Question 5:
5 | Where a candidate has misread a number in the question and used that value consistently throughout, provided that number does not alter the difficulty or
the method required, award all marks earned and deduct just 1 mark for the misread.
5 | 1 8 1
P(A) = , P(B) = = ,
2 24 3 | B1 | Both stated, accept unsimplified.
1
P(AB) =
6 | M1 | Evidence that independence properties not used.
1 1 1
P(A) × P(B) =  =
2 3 6
so events are independent | A1 | Evaluated and conclusion stated.
P(A) × P(B) and P(AB) seen.
3
Question | Answer | Marks | Guidance
Marco has four boxes labelled $K$, $L$, $M$ and $N$. He places them in a straight line in the order $K$, $L$, $M$, $N$ with $K$ on the left. Marco also has four coloured marbles: one is red, one is green, one is white and one is yellow. He places a single marble in each box, at random. Events $A$ and $B$ are defined as follows.

$A$: The white marble is in either box $L$ or box $M$.

$B$: The red marble is to the left of both the green marble and the yellow marble.

Determine whether or not events $A$ and $B$ are independent. [3]

\hfill \mbox{\textit{CAIE S1 2023 Q5 [3]}}