CAIE Further Paper 3 2024 November — Question 1 5 marks

Exam BoardCAIE
ModuleFurther Paper 3 (Further Paper 3)
Year2024
SessionNovember
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicProjectiles
TypeProjectile passing through given point
DifficultyChallenging +1.2 This is a standard projectile motion problem requiring substitution of two conditions into the trajectory equation to form simultaneous equations. While it involves algebraic manipulation and solving for two unknowns, the approach is methodical and the angle tan⁻¹(2) gives clean components. The 5-mark allocation and straightforward setup place it moderately above average difficulty but well within typical A-level mechanics scope.
Spec1.05a Sine, cosine, tangent: definitions for all arguments3.02i Projectile motion: constant acceleration model

A particle \(P\) is projected with speed \(u \text{ m s}^{-1}\) at an angle \(\tan^{-1} 2\) above the horizontal from a point \(O\) on a horizontal plane and moves freely under gravity. When \(P\) has travelled a distance \(56 \text{ m}\) horizontally from \(O\), it is at a vertical height \(H \text{ m}\) above the plane. When \(P\) has travelled a distance \(84 \text{ m}\) horizontally from \(O\), it is at a vertical height \(\frac{1}{2}H \text{ m}\) above the plane. Find, in either order, the value of \(u\) and the value of \(H\). [5]

Question 1:
AnswerMarks
1 1 
Use equation of trajectory with point (56, H) or 84, H
 2 
5g 1 5g
H =112− 562 or H =168− 842
AnswerMarks Guidance
2u2 2 2u2M1 For one equation with one error.
A1Both correct.
Eliminate to find u or HM1
u=35A1
H = 48A1
5
AnswerMarks Guidance
QuestionAnswer Marks
Question 1:
1 |  1 
Use equation of trajectory with point (56, H) or 84, H
 2 
5g 1 5g
H =112− 562 or H =168− 842
2u2 2 2u2 | M1 | For one equation with one error.
A1 | Both correct.
Eliminate to find u or H | M1
u=35 | A1
H = 48 | A1
5
Question | Answer | Marks | Guidance
A particle $P$ is projected with speed $u \text{ m s}^{-1}$ at an angle $\tan^{-1} 2$ above the horizontal from a point $O$ on a horizontal plane and moves freely under gravity. When $P$ has travelled a distance $56 \text{ m}$ horizontally from $O$, it is at a vertical height $H \text{ m}$ above the plane. When $P$ has travelled a distance $84 \text{ m}$ horizontally from $O$, it is at a vertical height $\frac{1}{2}H \text{ m}$ above the plane.

Find, in either order, the value of $u$ and the value of $H$. [5]

\hfill \mbox{\textit{CAIE Further Paper 3 2024 Q1 [5]}}