CAIE Further Paper 3 2023 November — Question 1 4 marks

Exam BoardCAIE
ModuleFurther Paper 3 (Further Paper 3)
Year2023
SessionNovember
Marks4
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicCircular Motion 1
TypeConical pendulum – horizontal circle in free space (no surface)
DifficultyStandard +0.3 This is a standard conical pendulum problem requiring resolution of forces (tension into horizontal and vertical components), application of circular motion (centripetal force = mv²/r), and elimination of tension. The setup is straightforward with cos θ given explicitly, making it slightly easier than average. It's a routine 4-mark question testing basic circular motion principles without requiring novel insight.
Spec6.05a Angular velocity: definitions

One end of a light inextensible string of length \(a\) is attached to a fixed point \(O\). The other end of the string is attached to a particle of mass \(m\). The string is taut and makes an angle \(\theta\) with the downward vertical through \(O\), where \(\cos \theta = \frac{2}{3}\). The particle moves in a horizontal circle with speed \(v\). Find \(v\) in terms of \(a\) and \(g\). [4]

Question 1:
AnswerMarks Guidance
1↑Tcosθ=mg B1
mv2
→ Tsinθ=
AnswerMarks
asinθB1
Eliminate T and substitute for 𝜃M1
v= 5ag
AnswerMarks
6A1
4
AnswerMarks Guidance
QuestionAnswer Marks
Question 1:
1 | ↑Tcosθ=mg | B1
mv2
→ Tsinθ=
asinθ | B1
Eliminate T and substitute for 𝜃 | M1
v= 5ag
6 | A1
4
Question | Answer | Marks | Guidance
One end of a light inextensible string of length $a$ is attached to a fixed point $O$. The other end of the string is attached to a particle of mass $m$. The string is taut and makes an angle $\theta$ with the downward vertical through $O$, where $\cos \theta = \frac{2}{3}$. The particle moves in a horizontal circle with speed $v$.

Find $v$ in terms of $a$ and $g$. [4]

\hfill \mbox{\textit{CAIE Further Paper 3 2023 Q1 [4]}}