CAIE Further Paper 3 2020 November — Question 2 5 marks

Exam BoardCAIE
ModuleFurther Paper 3 (Further Paper 3)
Year2020
SessionNovember
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicCircular Motion 2
TypeVertical circle: complete revolution conditions
DifficultyChallenging +1.2 This is a standard circular motion problem requiring application of energy conservation and the condition for completing a vertical circle (tension = 0 at top, v² = ag). The setup is typical for Further Mechanics, involving straightforward algebraic manipulation of well-known formulas across 5 marks, but requires careful bookkeeping of the energy equation and understanding of the 'just completes' condition.
Spec6.02i Conservation of energy: mechanical energy principle6.05d Variable speed circles: energy methods

\includegraphics{figure_2} A particle \(P\) is attached to one end of a light inextensible string of length \(a\). The other end of the string is attached to a fixed point \(O\). The particle \(P\) is held with the string taut and making an angle \(\theta\) with the downward vertical. The particle \(P\) is then projected with speed \(\frac{1}{2}\sqrt{5ag}\) perpendicular to the string and just completes a vertical circle (see diagram). Find the value of \(\cos\theta\). [5]

Question 2:
AnswerMarks
2mv2
At top, tension = 0, so mg = (v2 =ag)
AnswerMarks
aB1
1 mv2 = 1 mu2 −mga ( 1+cosθ)
AnswerMarks Guidance
2 2M1 A1 Energy equation
Substitute for u and v: ag = 16 .5ag−2ag ( 1+cosθ)
AnswerMarks Guidance
25M1 Eliminate
1
cosθ=
AnswerMarks
10A1
5
AnswerMarks Guidance
QuestionAnswer Marks
Question 2:
2 | mv2
At top, tension = 0, so mg = (v2 =ag)
a | B1
1 mv2 = 1 mu2 −mga ( 1+cosθ)
2 2 | M1 A1 | Energy equation
Substitute for u and v: ag = 16 .5ag−2ag ( 1+cosθ)
25 | M1 | Eliminate
1
cosθ=
10 | A1
5
Question | Answer | Marks | Guidance
\includegraphics{figure_2}

A particle $P$ is attached to one end of a light inextensible string of length $a$. The other end of the string is attached to a fixed point $O$. The particle $P$ is held with the string taut and making an angle $\theta$ with the downward vertical. The particle $P$ is then projected with speed $\frac{1}{2}\sqrt{5ag}$ perpendicular to the string and just completes a vertical circle (see diagram).

Find the value of $\cos\theta$. [5]

\hfill \mbox{\textit{CAIE Further Paper 3 2020 Q2 [5]}}