CAIE Further Paper 3 2020 November — Question 1 3 marks

Exam BoardCAIE
ModuleFurther Paper 3 (Further Paper 3)
Year2020
SessionNovember
Marks3
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicHooke's law and elastic energy
TypeElastic string on smooth inclined plane
DifficultyStandard +0.3 This is a standard energy conservation problem with Hooke's law on an inclined plane. Students need to equate gravitational PE lost to elastic PE gained, set up the equation ½(3mg/a)x² = mg·x·sin(θ), and solve the resulting quadratic. It's straightforward application of familiar techniques with no conceptual surprises, making it slightly easier than average for Further Maths.
Spec6.02g Hooke's law: T = k*x or T = lambda*x/l6.02h Elastic PE: 1/2 k x^26.02i Conservation of energy: mechanical energy principle

A particle \(P\) of mass \(m\) is placed on a fixed smooth plane which is inclined at an angle \(\theta\) to the horizontal. A light spring, of natural length \(a\) and modulus of elasticity \(3mg\), has one end attached to \(P\) and the other end attached to a fixed point \(O\) at the top of the plane. The spring lies along a line of greatest slope of the plane. The system is released from rest with the spring at its natural length. Find, in terms of \(a\) and \(\theta\), an expression for the greatest extension of the spring in the subsequent motion. [3]

Question 1:
AnswerMarks
11 3mgx2
Gain in EPE = .
AnswerMarks Guidance
2 aB1 EPE gain.
Loss in GPE = mgxsinθ
AnswerMarks Guidance
EquateM1 Equate energies
2
x= asinθ
AnswerMarks Guidance
3A1 Using forces scores B0M0A0
3
AnswerMarks Guidance
QuestionAnswer Marks
Question 1:
1 | 1 3mgx2
Gain in EPE = .
2 a | B1 | EPE gain.
Loss in GPE = mgxsinθ
Equate | M1 | Equate energies
2
x= asinθ
3 | A1 | Using forces scores B0M0A0
3
Question | Answer | Marks | Guidance
A particle $P$ of mass $m$ is placed on a fixed smooth plane which is inclined at an angle $\theta$ to the horizontal. A light spring, of natural length $a$ and modulus of elasticity $3mg$, has one end attached to $P$ and the other end attached to a fixed point $O$ at the top of the plane. The spring lies along a line of greatest slope of the plane. The system is released from rest with the spring at its natural length.

Find, in terms of $a$ and $\theta$, an expression for the greatest extension of the spring in the subsequent motion. [3]

\hfill \mbox{\textit{CAIE Further Paper 3 2020 Q1 [3]}}