CAIE M2 2017 June — Question 1 4 marks

Exam BoardCAIE
ModuleM2 (Mechanics 2)
Year2017
SessionJune
Marks4
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicProjectiles
TypeVelocity direction at specific time/point
DifficultyStandard +0.3 This is a straightforward projectile motion problem requiring resolution of velocity components and use of the tangent relationship. Students must find when tan(40°) = -v_y/v_x using standard kinematic equations, which is a routine application of mechanics principles with no novel insight required.
Spec3.02i Projectile motion: constant acceleration model

A particle is projected with speed \(20\,\text{m}\,\text{s}^{-1}\) at an angle of \(60°\) above the horizontal. Calculate the time after projection when the particle is descending at an angle of \(40°\) below the horizontal. [4]

Question 1:
AnswerMarks Guidance
1tan40 = v / 20cos60 M1
v = 10tan40 ( = 8.3909...)A1
–10tan40 = 20sin60 – gtM1 Uses v = u + at vertically
t = 1.27 sA1
Total:4
Question 1:
1 | tan40 = v / 20cos60 | M1
v = 10tan40 ( = 8.3909...) | A1
–10tan40 = 20sin60 – gt | M1 | Uses v = u + at vertically
t = 1.27 s | A1
Total: | 4
A particle is projected with speed $20\,\text{m}\,\text{s}^{-1}$ at an angle of $60°$ above the horizontal. Calculate the time after projection when the particle is descending at an angle of $40°$ below the horizontal. [4]

\hfill \mbox{\textit{CAIE M2 2017 Q1 [4]}}