| Exam Board | CAIE |
|---|---|
| Module | M2 (Mechanics 2) |
| Year | 2014 |
| Session | June |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Centre of Mass 1 |
| Type | L-shaped or composite rectangular lamina |
| Difficulty | Standard +0.8 This is a multi-part centre of mass question requiring integration to find centroids of composite shapes, likely involving both standard shapes and regions requiring calculus. While the techniques are standard M2 content, the multi-step nature and need to combine multiple regions with careful coordinate work places it moderately above average difficulty for A-level. |
| Answer | Marks |
|---|---|
| 4 (i) | 182 −(20cos40)2 =202 −(20cos40)2 |
| Answer | Marks |
|---|---|
| h = 3.8 m | M1 |
| Answer | Marks | Guidance |
|---|---|---|
| A1 | 2 | Uses vertical motion with |
| Answer | Marks | Guidance |
|---|---|---|
| Page 5 | Mark Scheme | Syllabus |
| GCE A LEVEL – May/June 2014 | 9709 | 52 |
| (ii) | V2 =182 −(20cos40)2 |
| Answer | Marks |
|---|---|
| t = 1.89 | M1 |
| Answer | Marks | Guidance |
|---|---|---|
| A1 | 6 | V is the vertical component of the |
Question 4:
--- 4 (i) ---
4 (i) | 182 −(20cos40)2 =202 −(20cos40)2
–2gh
h = 3.8 m
OR
2 2
m ×20 /2−m × 18 =mgh
h = 3.8 m | M1
A1
M1
A1 | 2 | Uses vertical motion with
v 2 =u 2−2gs
Uses energy equation
Page 5 | Mark Scheme | Syllabus | Paper
GCE A LEVEL – May/June 2014 | 9709 | 52
(ii) | V2 =182 −(20cos40)2
V = 9.4483
9.4483 = –9.4483 + gt
t = 1.89 s
x = 1.89 × 20cos40
x = 29(.0) m
OR
3.8=(20sin40)T−gT 2 /2
T = 2.23(0), 0.34(1)
t =2.23(0) – 0.34(1)
t = 1.89 | M1
A1
M1
A 1
M1
A 1
M1
A1
M1
A1 | 6 | V is the vertical component of the
velocity of P when P's speed is 18
M1 for using their V
M1 scored if their time is used
1
Uses s = ut+ at2
2\includegraphics{figure_4}
\begin{enumerate}[label=(\roman*)]
\item
\item
\end{enumerate}
\hfill \mbox{\textit{CAIE M2 2014 Q4}}