| Exam Board | CAIE |
|---|---|
| Module | M2 (Mechanics 2) |
| Year | 2014 |
| Session | June |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Centre of Mass 1 |
| Type | L-shaped or composite rectangular lamina |
| Difficulty | Standard +0.3 This is a standard centre of mass question from M2, likely involving finding the centre of mass of a composite shape or system of particles using the standard formula. While it requires careful calculation and understanding of the centre of mass concept, it follows a well-practiced procedure with no novel problem-solving required, making it slightly easier than average. |
| Answer | Marks |
|---|---|
| 1 | –12sinθ = 12sinθ – 1.6g |
| Answer | Marks |
|---|---|
| θ = 41.8° | M1 |
| Answer | Marks | Guidance |
|---|---|---|
| A1 | 2 | sin θ = (1.6g / 2)12 |
Question 1:
1 | –12sinθ = 12sinθ – 1.6g
θ = 41.8°
OR
0 = 12sin θ × 1.6 –1 × 10 × 1.6 2
2
θ = 41.8°
OR
0 = 12sinθ – 10 × 0.8
θ = 41.8° | M1
A1
M1
A1
M1
A1 | 2 | sin θ = (1.6g / 2)12
Uses s=ut+ 1at2
2
Uses v = u + at at the highest point\includegraphics{figure_1}
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\hfill \mbox{\textit{CAIE M2 2014 Q1}}