| Exam Board | CAIE |
|---|---|
| Module | Further Paper 2 (Further Paper 2) |
| Year | 2023 |
| Session | November |
| Marks | 10 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Parametric differentiation |
| Type | Find second derivative d²y/dx² |
| Difficulty | Challenging +1.2 This is a standard Further Maths parametric question requiring arc length calculation and second derivative analysis. Part (a) involves computing dx/dt and dy/dt, then integrating √(1+(dy/dx)²) which simplifies nicely. Part (b) requires finding d²y/dx² using the chain rule formula. While it requires multiple techniques and careful algebra, these are well-practiced procedures for Further Maths students with no novel insight needed. The 10 marks and straightforward setup place it moderately above average difficulty. |
| Spec | 1.07s Parametric and implicit differentiation4.08f Integrate using partial fractions |
| Answer | Marks |
|---|---|
| 5(a) | 1 1 |
| Answer | Marks | Guidance |
|---|---|---|
| x=t2 −t 2, y=2 | B1 | Differentiates x and y with respect to t. |
| Answer | Marks | Guidance |
|---|---|---|
| | M1 A1 | Factorises x2 + y2. |
| Answer | Marks | Guidance |
|---|---|---|
| 0 | M1 A1 | Applies correct formula for arc length. |
| Answer | Marks | Guidance |
|---|---|---|
| Question | Answer | Marks |
| Answer | Marks |
|---|---|
| 5(b) | dy y 2 |
| Answer | Marks | Guidance |
|---|---|---|
| t2 −t 2 | B1 | Finds first derivative. |
| Answer | Marks | Guidance |
|---|---|---|
| | B1 | dy |
| Answer | Marks | Guidance |
|---|---|---|
| | M1 A1 | Applies chain rule. OE. Does not have to be simplified |
| Answer | Marks | Guidance |
|---|---|---|
| 0t1 | A1 | Accept −1t1. CWO. |
| Answer | Marks | Guidance |
|---|---|---|
| Question | Answer | Marks |
Question 5:
--- 5(a) ---
5(a) | 1 1
−
x=t2 −t 2, y=2 | B1 | Differentiates x and y with respect to t.
2 2
1 1 1 1
− −
x2 + y2 =t2 −t 2 +4=t+2+t−1 =t2 +t 2
| M1 A1 | Factorises x2 + y2.
3
1 1 3 1
3 − 2
t2 +t 2dt = t2 +2t2 =4 3
0 3
0 | M1 A1 | Applies correct formula for arc length.
3
M1 for their x2 + y2 dt.
0
Answer must be simplified to 4 3 for A1.
5
Question | Answer | Marks | Guidance
--- 5(b) ---
5(b) | dy y 2
= =
dx x 1 1
−
t2 −t 2 | B1 | Finds first derivative.
1 3
1 − 1 −
−2 t 2 + t 2
d 2 2 2
=
dt 1 1 2
− 1 1
t2 −t 2 t2 −t − 2
| B1 | dy
Differentiates with respect to t.
dx
1 3
1 − 1 −
−2 t 2 + t 2
d2y d 2 dt 2 2 t+1
= = =−
dx2 dt 1 − 1 dx 1 1 3 (t−1)3
t2 −t 2 t2 −t − 2
| M1 A1 | Applies chain rule. OE. Does not have to be simplified
for A1.
0t1 | A1 | Accept −1t1. CWO.
5
Question | Answer | Marks | Guidance
The curve C has parametric equations
$$x = \frac{5}{3}t^{\frac{3}{2}} - 2t^{\frac{1}{2}}, \quad y = 2t + 5, \quad \text{for } 0 < t \leq 3.$$
\begin{enumerate}[label=(\alph*)]
\item Find the exact length of C. [5]
\item Find the set of values of $t$ for which $\frac{d^2y}{dx^2} > 0$. [5]
\end{enumerate}
\hfill \mbox{\textit{CAIE Further Paper 2 2023 Q5 [10]}}