CAIE FP1 2018 November — Question 9 10 marks

Exam BoardCAIE
ModuleFP1 (Further Pure Mathematics 1)
Year2018
SessionNovember
Marks10
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicPolar coordinates
TypeArea of region with line boundary
DifficultyStandard +0.8 This Further Maths polar coordinates question requires multiple techniques: area integration with a non-standard integrand (√cot θ), optimization to find maximum distance from initial line, and understanding polar curve behavior. While individual parts use standard methods, the combination of √cot θ (requiring trigonometric manipulation), finding extrema in polar form, and sketching an unfamiliar curve elevates this above routine exercises.
Spec4.09a Polar coordinates: convert to/from cartesian4.09b Sketch polar curves: r = f(theta)4.09c Area enclosed: by polar curve

The curve \(C\) has polar equation $$r = 5\sqrt{\cot \theta},$$ where \(0.01 \leqslant \theta \leqslant \frac{1}{2}\pi\).
  1. Find the area of the finite region bounded by \(C\) and the line \(\theta = 0.01\), showing full working. Give your answer correct to \(1\) decimal place. [3]
Let \(P\) be the point on \(C\) where \(\theta = 0.01\).
  1. Find the distance of \(P\) from the initial line, giving your answer correct to \(1\) decimal place. [2]
  2. Find the maximum distance of \(C\) from the initial line. [3]
  3. Sketch \(C\). [2]

Question 9:

AnswerMarks
9(i)π
25 2
∫ cotθ dθ
2
AnswerMarks Guidance
0.01M1 1
Uses ∫r2dθ.
2
π
25[ ]
= lnsinθ 2
AnswerMarks
2 0.01A1
25
=− lnsin0.01≈57.6
AnswerMarks
2A1
3

AnswerMarks
9(ii)1 1 5 1
y=5cos2θsin2θ= sin2 2θ
AnswerMarks Guidance
2M1 Uses y=rsinθ.
θ=0.01⇒ y≈0.5A1
2

AnswerMarks Guidance
9(iii)dy = 5 sin − 1 2 2θcos2θ=0 or max ( sin2θ )=1
dθ 2M1 A1 dy
Sets =0 or considers max (AEF).
⇒y= 5 2 (=3.54 )
AnswerMarks
2A1
3
AnswerMarks Guidance
QuestionAnswer Marks

AnswerMarks Guidance
9(iv)B1 Intersecting the initial line only when x = 0 and y = 0.
B1Correct shape.
2
AnswerMarks Guidance
QuestionAnswer Marks
Question 9:
--- 9(i) ---
9(i) | π
25 2
∫ cotθ dθ
2
0.01 | M1 | 1
Uses ∫r2dθ.
2
π
25[ ]
= lnsinθ 2
2 0.01 | A1
25
=− lnsin0.01≈57.6
2 | A1
3
--- 9(ii) ---
9(ii) | 1 1 5 1
y=5cos2θsin2θ= sin2 2θ
2 | M1 | Uses y=rsinθ.
θ=0.01⇒ y≈0.5 | A1
2
--- 9(iii) ---
9(iii) | dy = 5 sin − 1 2 2θcos2θ=0 or max ( sin2θ )=1
dθ 2 | M1 A1 | dy
Sets =0 or considers max (AEF).
dθ
⇒y= 5 2 (=3.54 )
2 | A1
3
Question | Answer | Marks | Guidance
--- 9(iv) ---
9(iv) | B1 | Intersecting the initial line only when x = 0 and y = 0.
B1 | Correct shape.
2
Question | Answer | Marks | Guidance
The curve $C$ has polar equation
$$r = 5\sqrt{\cot \theta},$$
where $0.01 \leqslant \theta \leqslant \frac{1}{2}\pi$.

\begin{enumerate}[label=(\roman*)]
\item Find the area of the finite region bounded by $C$ and the line $\theta = 0.01$, showing full working. Give your answer correct to $1$ decimal place. [3]
\end{enumerate}

Let $P$ be the point on $C$ where $\theta = 0.01$.

\begin{enumerate}[label=(\roman*)]
\setcounter{enumi}{1}
\item Find the distance of $P$ from the initial line, giving your answer correct to $1$ decimal place. [2]

\item Find the maximum distance of $C$ from the initial line. [3]

\item Sketch $C$. [2]
\end{enumerate}

\hfill \mbox{\textit{CAIE FP1 2018 Q9 [10]}}