| Exam Board | CAIE |
|---|---|
| Module | FP1 (Further Pure Mathematics 1) |
| Year | 2018 |
| Session | November |
| Marks | 8 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Invariant lines and eigenvalues and vectors |
| Type | Prove eigenvalue/eigenvector properties |
| Difficulty | Standard +0.8 This is a multi-part Further Maths question requiring understanding of eigenvalue properties and diagonalization. Part (i) is a straightforward proof using the definition of eigenvectors. Part (ii) requires routine matrix-vector multiplication. Part (iii) applies the result from (i) to construct a diagonalization, which is a standard technique but requires synthesis of the previous parts. The question is well-scaffolded and tests core FM concepts without requiring novel insight, placing it slightly above average difficulty. |
| Spec | 4.03h Determinant 2x2: calculation4.03i Determinant: area scale factor and orientation |
| Answer | Marks | Guidance |
|---|---|---|
| 5(i) | Ae=λe and Be=µe ⇒Ae+Be=λe+µe | M1 |
| ⇒ ( A+B ) e=( λ+µ) e | A1 |
| Answer | Marks |
|---|---|
| 5(ii) | 2 0 11 3 |
| Answer | Marks | Guidance |
|---|---|---|
| 1 0 21 3 | M1 | Multiples matrix with vector. |
| ⇒λ=3k | A1 | Finds one eigenvalue. |
| λ=1, 2 | A1 | Finds other two. |
| Answer | Marks |
|---|---|
| 5(iii) | 1 1 0 |
| Answer | Marks |
|---|---|
| 1 −1 0 | B1 |
| Answer | Marks | Guidance |
|---|---|---|
| | M1 A1 | Or correctly matched permutations of columns. |
| Answer | Marks | Guidance |
|---|---|---|
| Question | Answer | Marks |
Question 5:
--- 5(i) ---
5(i) | Ae=λe and Be=µe ⇒Ae+Be=λe+µe | M1 | Adds equations.
⇒ ( A+B ) e=( λ+µ) e | A1
2
--- 5(ii) ---
5(ii) | 2 0 11 3
−1 2 3 2 = 6
1 0 21 3 | M1 | Multiples matrix with vector.
⇒λ=3k | A1 | Finds one eigenvalue.
λ=1, 2 | A1 | Finds other two.
3
--- 5(iii) ---
5(iii) | 1 1 0
P= 2 4 1
1 −1 0 | B1
73 0 0 343 0 0
D= 0 63 0 = 0 216 0
0 0 33 0 0 27
| M1 A1 | Or correctly matched permutations of columns.
3
Question | Answer | Marks | Guidance
It is given that $\lambda$ is an eigenvalue of the matrix $\mathbf{A}$ with $\mathbf{e}$ as a corresponding eigenvector, and $\mu$ is an eigenvalue of the matrix $\mathbf{B}$ for which $\mathbf{e}$ is also a corresponding eigenvector.
\begin{enumerate}[label=(\roman*)]
\item Show that $\lambda + \mu$ is an eigenvalue of the matrix $\mathbf{A} + \mathbf{B}$ with $\mathbf{e}$ as a corresponding eigenvector. [2]
\end{enumerate}
The matrix $\mathbf{A}$, given by
$$\mathbf{A} = \begin{pmatrix} 2 & 0 & 1 \\ -1 & 2 & 3 \\ 1 & 0 & 2 \end{pmatrix}$$
has $\begin{pmatrix} 1 \\ 2 \\ 1 \end{pmatrix}$, $\begin{pmatrix} 1 \\ 4 \\ -1 \end{pmatrix}$ and $\begin{pmatrix} 0 \\ 1 \\ 0 \end{pmatrix}$ as eigenvectors.
\begin{enumerate}[label=(\roman*)]
\setcounter{enumi}{1}
\item Find the corresponding eigenvalues. [3]
\end{enumerate}
The matrix $\mathbf{B}$ has eigenvalues $4$, $5$ and $1$ with corresponding eigenvectors $\begin{pmatrix} 1 \\ 2 \\ 1 \end{pmatrix}$, $\begin{pmatrix} 1 \\ 4 \\ -1 \end{pmatrix}$ and $\begin{pmatrix} 0 \\ 1 \\ 0 \end{pmatrix}$ respectively.
\begin{enumerate}[label=(\roman*)]
\setcounter{enumi}{2}
\item Find a matrix $\mathbf{P}$ and a diagonal matrix $\mathbf{D}$ such that $(\mathbf{A} + \mathbf{B})^3 = \mathbf{P}\mathbf{D}\mathbf{P}^{-1}$. [3]
\end{enumerate}
\hfill \mbox{\textit{CAIE FP1 2018 Q5 [8]}}