CAIE FP1 2018 November — Question 5 8 marks

Exam BoardCAIE
ModuleFP1 (Further Pure Mathematics 1)
Year2018
SessionNovember
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicInvariant lines and eigenvalues and vectors
TypeProve eigenvalue/eigenvector properties
DifficultyStandard +0.8 This is a multi-part Further Maths question requiring understanding of eigenvalue properties and diagonalization. Part (i) is a straightforward proof using the definition of eigenvectors. Part (ii) requires routine matrix-vector multiplication. Part (iii) applies the result from (i) to construct a diagonalization, which is a standard technique but requires synthesis of the previous parts. The question is well-scaffolded and tests core FM concepts without requiring novel insight, placing it slightly above average difficulty.
Spec4.03h Determinant 2x2: calculation4.03i Determinant: area scale factor and orientation

It is given that \(\lambda\) is an eigenvalue of the matrix \(\mathbf{A}\) with \(\mathbf{e}\) as a corresponding eigenvector, and \(\mu\) is an eigenvalue of the matrix \(\mathbf{B}\) for which \(\mathbf{e}\) is also a corresponding eigenvector.
  1. Show that \(\lambda + \mu\) is an eigenvalue of the matrix \(\mathbf{A} + \mathbf{B}\) with \(\mathbf{e}\) as a corresponding eigenvector. [2]
The matrix \(\mathbf{A}\), given by $$\mathbf{A} = \begin{pmatrix} 2 & 0 & 1 \\ -1 & 2 & 3 \\ 1 & 0 & 2 \end{pmatrix}$$ has \(\begin{pmatrix} 1 \\ 2 \\ 1 \end{pmatrix}\), \(\begin{pmatrix} 1 \\ 4 \\ -1 \end{pmatrix}\) and \(\begin{pmatrix} 0 \\ 1 \\ 0 \end{pmatrix}\) as eigenvectors.
  1. Find the corresponding eigenvalues. [3]
The matrix \(\mathbf{B}\) has eigenvalues \(4\), \(5\) and \(1\) with corresponding eigenvectors \(\begin{pmatrix} 1 \\ 2 \\ 1 \end{pmatrix}\), \(\begin{pmatrix} 1 \\ 4 \\ -1 \end{pmatrix}\) and \(\begin{pmatrix} 0 \\ 1 \\ 0 \end{pmatrix}\) respectively.
  1. Find a matrix \(\mathbf{P}\) and a diagonal matrix \(\mathbf{D}\) such that \((\mathbf{A} + \mathbf{B})^3 = \mathbf{P}\mathbf{D}\mathbf{P}^{-1}\). [3]

Question 5:

AnswerMarks Guidance
5(i)Ae=λe and Be=µe ⇒Ae+Be=λe+µe M1
⇒ ( A+B ) e=( λ+µ) eA1
2

AnswerMarks
5(ii) 2 0 11 3
    
−1 2 3 2 = 6
    
    
AnswerMarks Guidance
 1 0 21 3M1 Multiples matrix with vector.
⇒λ=3kA1 Finds one eigenvalue.
λ=1, 2A1 Finds other two.
3

AnswerMarks
5(iii)1 1 0
 
P= 2 4 1
 
 
AnswerMarks
1 −1 0B1
73 0 0  343 0 0 
 
 
D=  0 63 0  = 0 216 0
 
   
 0 0 33  0 0 27
AnswerMarks Guidance
 M1 A1 Or correctly matched permutations of columns.
3
AnswerMarks Guidance
QuestionAnswer Marks
Question 5:
--- 5(i) ---
5(i) | Ae=λe and Be=µe ⇒Ae+Be=λe+µe | M1 | Adds equations.
⇒ ( A+B ) e=( λ+µ) e | A1
2
--- 5(ii) ---
5(ii) |  2 0 11 3
    
−1 2 3 2 = 6
    
    
 1 0 21 3 | M1 | Multiples matrix with vector.
⇒λ=3k | A1 | Finds one eigenvalue.
λ=1, 2 | A1 | Finds other two.
3
--- 5(iii) ---
5(iii) | 1 1 0
 
P= 2 4 1
 
 
1 −1 0 | B1
73 0 0  343 0 0 
 
 
D=  0 63 0  = 0 216 0
 
   
 0 0 33  0 0 27
  | M1 A1 | Or correctly matched permutations of columns.
3
Question | Answer | Marks | Guidance
It is given that $\lambda$ is an eigenvalue of the matrix $\mathbf{A}$ with $\mathbf{e}$ as a corresponding eigenvector, and $\mu$ is an eigenvalue of the matrix $\mathbf{B}$ for which $\mathbf{e}$ is also a corresponding eigenvector.

\begin{enumerate}[label=(\roman*)]
\item Show that $\lambda + \mu$ is an eigenvalue of the matrix $\mathbf{A} + \mathbf{B}$ with $\mathbf{e}$ as a corresponding eigenvector. [2]
\end{enumerate}

The matrix $\mathbf{A}$, given by
$$\mathbf{A} = \begin{pmatrix} 2 & 0 & 1 \\ -1 & 2 & 3 \\ 1 & 0 & 2 \end{pmatrix}$$

has $\begin{pmatrix} 1 \\ 2 \\ 1 \end{pmatrix}$, $\begin{pmatrix} 1 \\ 4 \\ -1 \end{pmatrix}$ and $\begin{pmatrix} 0 \\ 1 \\ 0 \end{pmatrix}$ as eigenvectors.

\begin{enumerate}[label=(\roman*)]
\setcounter{enumi}{1}
\item Find the corresponding eigenvalues. [3]
\end{enumerate}

The matrix $\mathbf{B}$ has eigenvalues $4$, $5$ and $1$ with corresponding eigenvectors $\begin{pmatrix} 1 \\ 2 \\ 1 \end{pmatrix}$, $\begin{pmatrix} 1 \\ 4 \\ -1 \end{pmatrix}$ and $\begin{pmatrix} 0 \\ 1 \\ 0 \end{pmatrix}$ respectively.

\begin{enumerate}[label=(\roman*)]
\setcounter{enumi}{2}
\item Find a matrix $\mathbf{P}$ and a diagonal matrix $\mathbf{D}$ such that $(\mathbf{A} + \mathbf{B})^3 = \mathbf{P}\mathbf{D}\mathbf{P}^{-1}$. [3]
\end{enumerate}

\hfill \mbox{\textit{CAIE FP1 2018 Q5 [8]}}