CAIE FP1 2003 November — Question 10 12 marks

Exam BoardCAIE
ModuleFP1 (Further Pure Mathematics 1)
Year2003
SessionNovember
Marks12
PaperDownload PDF ↗
TopicInvariant lines and eigenvalues and vectors
TypeFind P and D for A² = PDP⁻¹ or A⁻¹ = PDP⁻¹
DifficultyStandard +0.8 This is a substantial Further Maths question requiring eigenvalue/eigenvector calculation for a 3×3 matrix (solving a cubic characteristic equation), then applying diagonalization theory to express a matrix polynomial. The 'hence' part requires recognizing that A + A² + A³ = P(D + D² + D³)P⁻¹, which demands conceptual understanding beyond routine computation. Worth 12 marks total with multiple computational steps and theoretical insight.
Spec4.03n Inverse 2x2 matrix4.03o Inverse 3x3 matrix

Find the eigenvalues and corresponding eigenvectors of the matrix \(\mathbf{A}\), where $$\mathbf{A} = \begin{pmatrix} 6 & 4 & 1 \\ -6 & -1 & 3 \\ 8 & 8 & 4 \end{pmatrix}.$$ [8] Hence find a non-singular matrix \(\mathbf{P}\) and a diagonal matrix \(\mathbf{D}\) such that \(\mathbf{A} + \mathbf{A}^2 + \mathbf{A}^3 = \mathbf{PDP}^{-1}\). [4]

Find the eigenvalues and corresponding eigenvectors of the matrix $\mathbf{A}$, where
$$\mathbf{A} = \begin{pmatrix} 6 & 4 & 1 \\ -6 & -1 & 3 \\ 8 & 8 & 4 \end{pmatrix}.$$ [8]

Hence find a non-singular matrix $\mathbf{P}$ and a diagonal matrix $\mathbf{D}$ such that $\mathbf{A} + \mathbf{A}^2 + \mathbf{A}^3 = \mathbf{PDP}^{-1}$. [4]

\hfill \mbox{\textit{CAIE FP1 2003 Q10 [12]}}