CAIE P3 2018 November — Question 4 7 marks

Exam BoardCAIE
ModuleP3 (Pure Mathematics 3)
Year2018
SessionNovember
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicParametric differentiation
TypeTangent parallel to axis condition
DifficultyStandard +0.3 This is a straightforward parametric differentiation question requiring standard application of dy/dx = (dy/dθ)/(dx/dθ), followed by solving for when dx/dθ = 0. The trigonometric differentiation and simplification are routine, and finding where the tangent is vertical is a standard technique. Slightly above average difficulty due to the double angle terms and algebraic manipulation required, but no novel insight needed.
Spec1.03g Parametric equations: of curves and conversion to cartesian1.07s Parametric and implicit differentiation

The parametric equations of a curve are $$x = 2\sin\theta + \sin 2\theta, \quad y = 2\cos\theta + \cos 2\theta,$$ where \(0 < \theta < \pi\).
  1. Obtain an expression for \(\frac{dy}{dx}\) in terms of \(\theta\). [3]
  2. Hence find the exact coordinates of the point on the curve at which the tangent is parallel to the \(y\)-axis. [4]

Question 4:

AnswerMarks
4(i)dx dy
Obtain =2cosθ+2cos2θ or = −2sinθ−2sin2θ
AnswerMarks
dθ dθB1
Use dy/dx = dy/dθ ÷ dx/dθM1
dy 2sinθ+2sin2θ
Obtain correct in any form, e.g. –
AnswerMarks
dx 2cosθ+2cos2θA1
3

AnswerMarks Guidance
4(ii)Equate denominator to zero and use any correct double angle formula M1*
Obtain correct 3-term quadratic in cos θ in any formA1
Solve for θdepM1*
1
Obtain x = 3 3/2 and y = , or exact equivalents
AnswerMarks
2A1
4
AnswerMarks Guidance
QuestionAnswer Marks
Question 4:
--- 4(i) ---
4(i) | dx dy
Obtain =2cosθ+2cos2θ or = −2sinθ−2sin2θ
dθ dθ | B1
Use dy/dx = dy/dθ ÷ dx/dθ | M1
dy 2sinθ+2sin2θ
Obtain correct in any form, e.g. –
dx 2cosθ+2cos2θ | A1
3
--- 4(ii) ---
4(ii) | Equate denominator to zero and use any correct double angle formula | M1*
Obtain correct 3-term quadratic in cos θ in any form | A1
Solve for θ | depM1*
1
Obtain x = 3 3/2 and y = , or exact equivalents
2 | A1
4
Question | Answer | Marks | Guidance
The parametric equations of a curve are
$$x = 2\sin\theta + \sin 2\theta, \quad y = 2\cos\theta + \cos 2\theta,$$
where $0 < \theta < \pi$.

\begin{enumerate}[label=(\roman*)]
\item Obtain an expression for $\frac{dy}{dx}$ in terms of $\theta$. [3]

\item Hence find the exact coordinates of the point on the curve at which the tangent is parallel to the $y$-axis. [4]
\end{enumerate}

\hfill \mbox{\textit{CAIE P3 2018 Q4 [7]}}