CAIE P3 2018 June — Question 8 8 marks

Exam BoardCAIE
ModuleP3 (Pure Mathematics 3)
Year2018
SessionJune
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicTangents, normals and gradients
TypeTangent parallel to given line
DifficultyModerate -0.3 Part (i) requires finding where dy/dx equals -3, solving a quadratic, then writing the tangent equation—standard differentiation and coordinate geometry. Part (ii) asks for the smallest k where f is increasing, requiring setting f'(x) ≥ 0 and solving—a routine application of calculus concepts. Both parts are straightforward applications of A-level techniques with no novel problem-solving required, making this slightly easier than average.
Spec1.07m Tangents and normals: gradient and equations1.07o Increasing/decreasing: functions using sign of dy/dx

  1. The tangent to the curve \(y = x^3 - 9x^2 + 24x - 12\) at a point \(A\) is parallel to the line \(y = 2 - 3x\). Find the equation of the tangent at \(A\). [6]
  2. The function f is defined by \(\mathrm{f}(x) = x^3 - 9x^2 + 24x - 12\) for \(x > k\), where \(k\) is a constant. Find the smallest value of \(k\) for f to be an increasing function. [2]

Question 8:

AnswerMarks
8(i)dy
State or imply 3y2 as derivative of y3
AnswerMarks
dxB1
dy
State or imply 3y2 +6xy as derivative of 3xy2
AnswerMarks
dxB1
dy
Equate derivative of LHS to zero and solve for
AnswerMarks
dxM1
Obtain the given answerA1
Total:4

AnswerMarks Guidance
8(ii)Equate denominator to zero and solve for y M1*
Obtain y = 0 and x = aA1
Obtain y = αx and substitute in curve equation to find x or
AnswerMarks Guidance
to find yM1(dep*)
Obtain x = – aA1
Obtain y = 2aA1
Total:5
QuestionAnswer Marks
Question 8:
--- 8(i) ---
8(i) | dy
State or imply 3y2 as derivative of y3
dx | B1
dy
State or imply 3y2 +6xy as derivative of 3xy2
dx | B1
dy
Equate derivative of LHS to zero and solve for
dx | M1
Obtain the given answer | A1
Total: | 4
--- 8(ii) ---
8(ii) | Equate denominator to zero and solve for y | M1*
Obtain y = 0 and x = a | A1
Obtain y = αx and substitute in curve equation to find x or
to find y | M1(dep*)
Obtain x = – a | A1
Obtain y = 2a | A1
Total: | 5
Question | Answer | Marks
\begin{enumerate}[label=(\roman*)]
\item The tangent to the curve $y = x^3 - 9x^2 + 24x - 12$ at a point $A$ is parallel to the line $y = 2 - 3x$. Find the equation of the tangent at $A$. [6]

\item The function f is defined by $\mathrm{f}(x) = x^3 - 9x^2 + 24x - 12$ for $x > k$, where $k$ is a constant. Find the smallest value of $k$ for f to be an increasing function. [2]
\end{enumerate}

\hfill \mbox{\textit{CAIE P3 2018 Q8 [8]}}