CAIE P3 2017 June — Question 9 11 marks

Exam BoardCAIE
ModuleP3 (Pure Mathematics 3)
Year2017
SessionJune
Marks11
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicVectors: Cross Product & Distances
TypeFind foot of perpendicular from point to line
DifficultyStandard +0.3 This is a standard multi-part vectors question testing routine techniques: finding foot of perpendicular (dot product condition), reflection (midpoint), plane equation (cross product of two direction vectors), and point-to-plane distance (formula application). All methods are textbook procedures with no novel insight required, making it slightly easier than average despite being Further Maths content.
Spec4.04a Line equations: 2D and 3D, cartesian and vector forms4.04b Plane equations: cartesian and vector forms4.04c Scalar product: calculate and use for angles4.04j Shortest distance: between a point and a plane

Relative to the origin \(O\), the point \(A\) has position vector given by \(\overrightarrow{OA} = \mathbf{i} + 2\mathbf{j} + 4\mathbf{k}\). The line \(l\) has equation \(\mathbf{r} = 9\mathbf{i} - \mathbf{j} + 8\mathbf{k} + \mu(3\mathbf{i} - \mathbf{j} + 2\mathbf{k})\).
  1. Find the position vector of the foot of the perpendicular from \(A\) to \(l\). Hence find the position vector of the reflection of \(A\) in \(l\). [5]
  2. Find the equation of the plane through the origin which contains \(l\). Give your answer in the form \(ax + by + cz = d\). [3]
  3. Find the exact value of the perpendicular distance of \(A\) from this plane. [3]

Question 9:

AnswerMarks
9(i)EITHER:
uuur
AnswerMarks
FindAPfor a general point P on l with parameter λ , e.g.(8 + 3λ, – 3 − λ, 4 + 2λ)(B1
uuur
AnswerMarks
Equate scalar product of APand direction vector of l to zero and solve for λM1
Obtainλ=− 5 and foot of perpendicular 3 i+ 3 j+3k
AnswerMarks Guidance
2 2 2A1
Carry out a complete method for finding the position vector of the reflection of A in lM1
Obtain answer 2i+j+2kA1)
QuestionAnswer Marks
OR:
uuur
AnswerMarks
FindAPfor a general point P on l with parameter λ , e.g.(8 + 3λ, – 3 − λ, 4 + 2λ)(B1
AP2
AnswerMarks
Differentiate and solve for λ at minimumM1
Obtainλ=− 5 and foot of perpendicular 3 i+ 3 j+3k
AnswerMarks
2 2 2A1
Carry out a complete method for finding the position vector of the reflection of A in lM1
Obtain answer 2i+j+2kA1)
Total:5

AnswerMarks
9(ii)EITHER:
Use scalar product to obtain an equation in a, b and c, e.g. 3a − b + 2 c = 0(B1
Form a second relevant equation, e.g. 9a – b + 8c = 0 and solve for one ratio, e.g. a : bM1
Obtain final answer a : b : c = 1 : 1 : – 1 and state plane equation x + y – z = 0A1)
OR1:
AnswerMarks
Attempt to calculate vector product of two relevant vectors, e.g. (3i−j+2k)×(9i−j+8k)(M1
Obtain two correct componentsA1
Obtain correct answer, e.g. −6i−6j+6k , and state plane equation −x−y+z=0A1)
OR2:
Using a relevant point and relevant vectors, attempt to form a 2-parameter equation for the
r=6i+6k+s(3i−j+2k)+t(9i−j+8k)
AnswerMarks
plane, e.g.(M1
State 3 correct equations in x, y, z, s and tA1
x+ y−z=0
AnswerMarks
Eliminate s and t and state plane equation , or equivalentA1)
OR3:
Using a relevant point and relevant vectors, attempt to form a determinant equation for the
x−3 y−1 z−4
plane, e.g. 3 −1 2 =0
AnswerMarks Guidance
9 −1 8(M1
Expand a correct determinant and obtain two correct cofactorsA1
Obtain answer −6x−6y+6z=0, or equivalentA1)
Total:3
QuestionAnswer Marks

AnswerMarks
9(iii)EITHER:
uuur
Using the correct processes, divide the scalar product of OAand a normal to the plane by the
AnswerMarks
modulus of the normal or make a recognisable attempt to apply the perpendicular formula(M1
1+2−4
Obtain a correct expression in any form, e.g. , or equivalent
2+1 2+(−1) 2
AnswerMarks
(1 )A1 FT
Obtain answer 1 3, or exact equivalentA1)
OR1:
Obtain equation of the parallel plane through A, e.g. x + y – z = – 1
AnswerMarks
[The f.t. is on the plane found in part (ii).](B1 FT
Use correct method to find its distance from the originM1
Obtain answer 1 3, or exact equivalentA1)
OR2:
Form equation for the intersection of the perpendicular through A and the plane
AnswerMarks
[FT on their n](B1 FT
Solve for λM1
1
λn =
AnswerMarks
3A1)
Total:3
Question 9:
--- 9(i) ---
9(i) | EITHER:
uuur
FindAPfor a general point P on l with parameter λ , e.g.(8 + 3λ, – 3 − λ, 4 + 2λ) | (B1
uuur
Equate scalar product of APand direction vector of l to zero and solve for λ | M1
Obtainλ=− 5 and foot of perpendicular 3 i+ 3 j+3k
2 2 2 | A1
Carry out a complete method for finding the position vector of the reflection of A in l | M1
Obtain answer 2i+j+2k | A1)
Question | Answer | Marks
OR:
uuur
FindAPfor a general point P on l with parameter λ , e.g.(8 + 3λ, – 3 − λ, 4 + 2λ) | (B1
AP2
Differentiate and solve for λ at minimum | M1
Obtainλ=− 5 and foot of perpendicular 3 i+ 3 j+3k
2 2 2 | A1
Carry out a complete method for finding the position vector of the reflection of A in l | M1
Obtain answer 2i+j+2k | A1)
Total: | 5
--- 9(ii) ---
9(ii) | EITHER:
Use scalar product to obtain an equation in a, b and c, e.g. 3a − b + 2 c = 0 | (B1
Form a second relevant equation, e.g. 9a – b + 8c = 0 and solve for one ratio, e.g. a : b | M1
Obtain final answer a : b : c = 1 : 1 : – 1 and state plane equation x + y – z = 0 | A1)
OR1:
Attempt to calculate vector product of two relevant vectors, e.g. (3i−j+2k)×(9i−j+8k) | (M1
Obtain two correct components | A1
Obtain correct answer, e.g. −6i−6j+6k , and state plane equation −x−y+z=0 | A1)
OR2:
Using a relevant point and relevant vectors, attempt to form a 2-parameter equation for the
r=6i+6k+s(3i−j+2k)+t(9i−j+8k)
plane, e.g. | (M1
State 3 correct equations in x, y, z, s and t | A1
x+ y−z=0
Eliminate s and t and state plane equation , or equivalent | A1)
OR3:
Using a relevant point and relevant vectors, attempt to form a determinant equation for the
x−3 y−1 z−4
plane, e.g. 3 −1 2 =0
9 −1 8 | (M1
Expand a correct determinant and obtain two correct cofactors | A1
Obtain answer −6x−6y+6z=0, or equivalent | A1)
Total: | 3
Question | Answer | Marks
--- 9(iii) ---
9(iii) | EITHER:
uuur
Using the correct processes, divide the scalar product of OAand a normal to the plane by the
modulus of the normal or make a recognisable attempt to apply the perpendicular formula | (M1
1+2−4
Obtain a correct expression in any form, e.g. , or equivalent
2+1 2+(−1) 2
(1 ) | A1 FT
Obtain answer 1 3, or exact equivalent | A1)
OR1:
Obtain equation of the parallel plane through A, e.g. x + y – z = – 1
[The f.t. is on the plane found in part (ii).] | (B1 FT
Use correct method to find its distance from the origin | M1
Obtain answer 1 3, or exact equivalent | A1)
OR2:
Form equation for the intersection of the perpendicular through A and the plane
[FT on their n] | (B1 FT
Solve for λ | M1
1
λn =
3 | A1)
Total: | 3
Relative to the origin $O$, the point $A$ has position vector given by $\overrightarrow{OA} = \mathbf{i} + 2\mathbf{j} + 4\mathbf{k}$. The line $l$ has equation $\mathbf{r} = 9\mathbf{i} - \mathbf{j} + 8\mathbf{k} + \mu(3\mathbf{i} - \mathbf{j} + 2\mathbf{k})$.

\begin{enumerate}[label=(\roman*)]
\item Find the position vector of the foot of the perpendicular from $A$ to $l$. Hence find the position vector of the reflection of $A$ in $l$. [5]

\item Find the equation of the plane through the origin which contains $l$. Give your answer in the form $ax + by + cz = d$. [3]

\item Find the exact value of the perpendicular distance of $A$ from this plane. [3]
\end{enumerate}

\hfill \mbox{\textit{CAIE P3 2017 Q9 [11]}}