CAIE P3 2017 June — Question 5 8 marks

Exam BoardCAIE
ModuleP3 (Pure Mathematics 3)
Year2017
SessionJune
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicDifferential equations
TypeChemical reaction kinetics
DifficultyStandard +0.3 This is a straightforward separable differential equation requiring substitution of the given expression for x, separation of variables, integration (including ln), and application of initial conditions. Part (ii) involves simple limit evaluation. While it requires multiple steps and careful algebraic manipulation, it follows standard A-level techniques without requiring novel insight or particularly challenging integration.
Spec1.08k Separable differential equations: dy/dx = f(x)g(y)

In a certain chemical process a substance \(A\) reacts with and reduces a substance \(B\). The masses of \(A\) and \(B\) at time \(t\) after the start of the process are \(x\) and \(y\) respectively. It is given that \(\frac{dy}{dt} = -0.2xy\) and \(x = \frac{10}{(1 + t)^2}\). At the beginning of the process \(y = 100\).
  1. Form a differential equation in \(y\) and \(t\), and solve this differential equation. [6]
  2. Find the exact value approached by the mass of \(B\) as \(t\) becomes large. State what happens to the mass of \(A\) as \(t\) becomes large. [2]

Question 5:

AnswerMarks
5(i)dy 2y
State =− , or equivalent
AnswerMarks
dt (1+t)2B1
Separate variables correctly and attempt integration of one sideM1
Obtain term lny, or equivalentA1
2
Obtain term , or equivalent
AnswerMarks
(1+t)A1
Use y = 100 and t = 0 to evaluate a constant, or as limits in an expression containing terms of
b
the form alny and
AnswerMarks
1+tM1
2
Obtain correct solution in any form, e.g. lny= −2+ln100
AnswerMarks
1+tA1
Total:6

AnswerMarks
5(ii)100
State that the mass of B approaches , or exact equivalent
AnswerMarks Guidance
e2B1
State or imply that the mass of A tends to zeroB1
Total:2
QuestionAnswer Marks
Question 5:
--- 5(i) ---
5(i) | dy 2y
State =− , or equivalent
dt (1+t)2 | B1
Separate variables correctly and attempt integration of one side | M1
Obtain term lny, or equivalent | A1
2
Obtain term , or equivalent
(1+t) | A1
Use y = 100 and t = 0 to evaluate a constant, or as limits in an expression containing terms of
b
the form alny and
1+t | M1
2
Obtain correct solution in any form, e.g. lny= −2+ln100
1+t | A1
Total: | 6
--- 5(ii) ---
5(ii) | 100
State that the mass of B approaches , or exact equivalent
e2 | B1
State or imply that the mass of A tends to zero | B1
Total: | 2
Question | Answer | Marks
In a certain chemical process a substance $A$ reacts with and reduces a substance $B$. The masses of $A$ and $B$ at time $t$ after the start of the process are $x$ and $y$ respectively. It is given that $\frac{dy}{dt} = -0.2xy$ and $x = \frac{10}{(1 + t)^2}$. At the beginning of the process $y = 100$.

\begin{enumerate}[label=(\roman*)]
\item Form a differential equation in $y$ and $t$, and solve this differential equation. [6]

\item Find the exact value approached by the mass of $B$ as $t$ becomes large. State what happens to the mass of $A$ as $t$ becomes large. [2]
\end{enumerate}

\hfill \mbox{\textit{CAIE P3 2017 Q5 [8]}}