CAIE P3 2024 November — Question 6 4 marks

Exam BoardCAIE
ModuleP3 (Pure Mathematics 3)
Year2024
SessionNovember
Marks4
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicExponential Equations & Modelling
Typeln(y) vs x: find constants from two points
DifficultyModerate -0.3 This is a straightforward logarithmic transformation question requiring students to recognize that ln(ay) = ln(a) + x·ln(b) gives a linear relationship, then use two points to find the gradient (ln b) and intercept (ln a). The algebra is routine and the question explicitly tells students the relationship is linear, removing any problem-solving element. Slightly easier than average due to its mechanical nature, though the exponential context and need to work backwards from ln values provides minor challenge.
Spec1.03a Straight lines: equation forms y=mx+c, ax+by+c=01.06h Logarithmic graphs: reduce y=ax^n and y=kb^x to linear form

\includegraphics{figure_6} The variables \(x\) and \(y\) satisfy the equation \(ay = b^x\), where \(a\) and \(b\) are constants. The graph of \(\ln y\) against \(x\) is a straight line passing through the points \((0.50, 2.24)\) and \((3.40, 8.27)\), as shown in the diagram. Find the values of \(a\) and \(b\). Give each value correct to 1 significant figure. [4]

Question 6:
AnswerMarks Guidance
6Form a pair of equations in a and b *M1
coordinates correctly.
lna+8.27=3.4lnb
e.g. 
lna+2.24=0.5lnb
ae2.24 =b0.5
or
ae8.27 =b3.4
AnswerMarks Guidance
Carry out a correct method for finding lna or lnb or a or bDM1 Condone sign slip.
Obtain value a = 0.3A1 (0.30109…)
Obtain value b = 8A1 (7.99895…)
Allow A0A1 if both values ‘correct’ but not
rounded to 1 sf.
Allow 4/4 for 0.3y=8x with correct working
shown.
AnswerMarks Guidance
QuestionAnswer Marks
6Alternative Method for Question 6:
Carry out a correct method for finding lnb or b
AnswerMarks Guidance
(Need to link the gradient to lnb at some point)*M1 Condone sign slips but must be using the given
coordinates correctly.
8.27−2.24
lnb= (=2.079....)
3.4−0.5
AnswerMarks Guidance
Obtain value b = 8A1
Correct method to find lnaor aDM1 (lna=−1.200...).
Condone sign slip
AnswerMarks Guidance
Obtain value a = 0.3A1 Allow A0A1 if both values ‘correct’ but not
rounded to 1 sf.
Allow 4/4 for 0.3y=8x with correct working
shown.
4
AnswerMarks Guidance
QuestionAnswer Marks
Question 6:
6 | Form a pair of equations in a and b | *M1 | Condone sign slips but must be using the given
coordinates correctly.
lna+8.27=3.4lnb
e.g. 
lna+2.24=0.5lnb
ae2.24 =b0.5
or
ae8.27 =b3.4
Carry out a correct method for finding lna or lnb or a or b | DM1 | Condone sign slip.
Obtain value a = 0.3 | A1 | (0.30109…)
Obtain value b = 8 | A1 | (7.99895…)
Allow A0A1 if both values ‘correct’ but not
rounded to 1 sf.
Allow 4/4 for 0.3y=8x with correct working
shown.
Question | Answer | Marks | Guidance
6 | Alternative Method for Question 6:
Carry out a correct method for finding lnb or b
(Need to link the gradient to lnb at some point) | *M1 | Condone sign slips but must be using the given
coordinates correctly.
8.27−2.24
lnb= (=2.079....)
3.4−0.5
Obtain value b = 8 | A1
Correct method to find lnaor a | DM1 | (lna=−1.200...).
Condone sign slip
Obtain value a = 0.3 | A1 | Allow A0A1 if both values ‘correct’ but not
rounded to 1 sf.
Allow 4/4 for 0.3y=8x with correct working
shown.
4
Question | Answer | Marks | Guidance
\includegraphics{figure_6}

The variables $x$ and $y$ satisfy the equation $ay = b^x$, where $a$ and $b$ are constants. The graph of $\ln y$ against $x$ is a straight line passing through the points $(0.50, 2.24)$ and $(3.40, 8.27)$, as shown in the diagram.

Find the values of $a$ and $b$. Give each value correct to 1 significant figure. [4]

\hfill \mbox{\textit{CAIE P3 2024 Q6 [4]}}