Moderate -0.8 This is a straightforward partial fractions question with a proper fraction (numerator degree less than denominator), linear distinct factors, and standard coefficients. It requires routine algebraic manipulation to find constants A and B, making it easier than average with no conceptual challenges or problem-solving required.
Question 5:
5 | B C
State or imply the form A
x1 2x1 | B1
Use a correct method for finding a constant | M1 | Correct appropriate method.
Obtain one of A = 3, B = 2 and C = –3 | A1
Obtain a second value | A1
Obtain a third value | A1
Alternative Method for Question 5
Divide numerator by denominator to reach A = 3 | (M1) | axb
May be implied by 3 [+] with a and b not both 0.
x12x1
x5
Obtain 3 +
x12x1 | (A1)
D E
State or imply the form
x1 2x1 | (B1)
Obtain one of D = 2 and E = − 3 | (A1)
Obtain a second value | (A1)
5
Question | Answer | Marks | Guidance