CAIE P2 2024 March — Question 1 4 marks

Exam BoardCAIE
ModuleP2 (Pure Mathematics 2)
Year2024
SessionMarch
Marks4
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicExponential Equations & Modelling
TypeSimple exponential equation solving
DifficultyModerate -0.5 This is a straightforward logarithmic equation requiring a standard technique: take logs of both sides, apply log laws, collect terms in t, and solve. It's slightly easier than average because it's a direct application of a single method with no conceptual complications, though the algebraic manipulation requires care.
Spec1.06f Laws of logarithms: addition, subtraction, power rules1.06g Equations with exponentials: solve a^x = b

Use logarithms to solve the equation \(3^{4t+3} = 5^{2t+7}\). Give your answer correct to 3 significant figures. [4]

Question 1:
AnswerMarks Guidance
1Apply logarithms to both sides and apply power law at least once *M1
Obtain (4x+3)ln3=(2x+7)ln5A1 Or equivalent with x not in a power.
Attempt solution of linear equationDM1
Obtain 6.78A1 Or greater accuracy.
4
AnswerMarks Guidance
QuestionAnswer Marks
Question 1:
1 | Apply logarithms to both sides and apply power law at least once | *M1
Obtain (4x+3)ln3=(2x+7)ln5 | A1 | Or equivalent with x not in a power.
Attempt solution of linear equation | DM1
Obtain 6.78 | A1 | Or greater accuracy.
4
Question | Answer | Marks | Guidance
Use logarithms to solve the equation $3^{4t+3} = 5^{2t+7}$. Give your answer correct to 3 significant figures. [4]

\hfill \mbox{\textit{CAIE P2 2024 Q1 [4]}}