Standard +0.3 This is a straightforward exponential equation requiring taking logarithms of both sides, expanding using log laws, collecting terms in x, and solving. It's slightly above routine because it involves both exponential bases (6 and e) and requires careful algebraic manipulation, but follows a standard algorithm taught explicitly in P2 with no conceptual difficulty or problem-solving insight needed.
Use logarithms to solve the equation $6^{2x-1} = 5e^{3x+2}$. Give your answer correct to 4 significant figures. [4]
\hfill \mbox{\textit{CAIE P2 2024 Q2 [4]}}