A curve is defined by the parametric equations
$$x = 4\cos^2 t, \quad y = \sqrt{3}\sin 2t,$$
for values of \(t\) such that \(0 < t < \frac{1}{2}\pi\).
Find the equation of the normal to the curve at the point for which \(t = \frac{1}{6}\pi\). Give your answer in the form \(ax + by + c = 0\) where \(a\), \(b\) and \(c\) are integers. [7]