CAIE P1 2017 June — Question 7 7 marks

Exam BoardCAIE
ModuleP1 (Pure Mathematics 1)
Year2017
SessionJune
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicRadians, Arc Length and Sector Area
TypeMultiple circles or sectors
DifficultyStandard +0.3 This is a straightforward geometry problem requiring basic trigonometry (inverse cosine to find the angle) and standard sector/triangle area formulas. Part (i) is a simple right-angle triangle calculation, and part (ii) involves computing two sectors minus two triangles—routine application of formulas with no novel insight required. Slightly easier than average due to the clear setup and standard techniques.
Spec1.05d Radians: arc length s=r*theta and sector area A=1/2 r^2 theta1.08e Area between curve and x-axis: using definite integrals

\includegraphics{figure_7} The diagram shows two circles with centres \(A\) and \(B\) having radii 8 cm and 10 cm respectively. The two circles intersect at \(C\) and \(D\) where \(CAD\) is a straight line and \(AB\) is perpendicular to \(CD\).
  1. Find angle \(ABC\) in radians. [1]
  2. Find the area of the shaded region. [6]

Question 7:

AnswerMarks Guidance
7(i)sinABC =8/10 → ABC =0.927 ( 3 ) B1
Total:1

AnswerMarks Guidance
7(ii)AB=6 ( Pythagoras ) → ∆BCD=8×6=48.0 M1A1
BCD=½×102×( )×their0.9273
AnswerMarks Guidance
Area sector 2*M1 Expect 92.7(3). 46.4 gets M1
Area segment = 92.7(3) – 48*A1 Expect 44.7(3). Might not appear until final calculation.
Area semi-circle ‒ segment = ½×π×82 −their ( 92.7−48 )DM1 ( )
Dep. on previous M1A1 OR π×82 − ½×π×82 +their44.7 .
AnswerMarks Guidance
Shaded area = 55.8 – 56.0A1
Total:6
QuestionAnswer Marks
Question 7:
--- 7(i) ---
7(i) | sinABC =8/10 → ABC =0.927 ( 3 ) | B1 | Or cos = 6/10 or tan = 8/6. Accept 0.295π.
Total: | 1
--- 7(ii) ---
7(ii) | AB=6 ( Pythagoras ) → ∆BCD=8×6=48.0 | M1A1 | OR 8×10sin0.6435 or ½×10×10sin((2)×0.927)=48. 24or 40or80 gets M1A0
BCD=½×102×( )×their0.9273
Area sector 2 | *M1 | Expect 92.7(3). 46.4 gets M1
Area segment = 92.7(3) – 48 | *A1 | Expect 44.7(3). Might not appear until final calculation.
Area semi-circle ‒ segment = ½×π×82 −their ( 92.7−48 ) | DM1 | ( )
Dep. on previous M1A1 OR π×82 − ½×π×82 +their44.7 .
Shaded area = 55.8 – 56.0 | A1
Total: | 6
Question | Answer | Marks | Guidance
\includegraphics{figure_7}

The diagram shows two circles with centres $A$ and $B$ having radii 8 cm and 10 cm respectively. The two circles intersect at $C$ and $D$ where $CAD$ is a straight line and $AB$ is perpendicular to $CD$.

\begin{enumerate}[label=(\roman*)]
\item Find angle $ABC$ in radians. [1]
\item Find the area of the shaded region. [6]
\end{enumerate}

\hfill \mbox{\textit{CAIE P1 2017 Q7 [7]}}