The function f is defined for \(x \geqslant 0\). It is given that f has a minimum value when \(x = 2\) and that \(\text{f}''(x) = (4x + 1)^{-\frac{1}{2}}\).
- Find \(\text{f}'(x)\). [3]
It is now given that \(\text{f}''(0)\), \(\text{f}'(0)\) and \(\text{f}(0)\) are the first three terms respectively of an arithmetic progression.
- Find the value of \(\text{f}(0)\). [3]
- Find \(\text{f}(x)\), and hence find the minimum value of f. [5]