CAIE P1 2015 June — Question 8 9 marks

Exam BoardCAIE
ModuleP1 (Pure Mathematics 1)
Year2015
SessionJune
Marks9
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicTrig Graphs & Exact Values
TypeSolve trigonometric equation with approximate values
DifficultyModerate -0.3 This is a straightforward multi-part question on transformed trigonometric functions. Part (i) requires basic equation solving with inverse cosine, (ii) is a standard graph sketch with vertical shift and horizontal stretch, (iii) tests understanding of one-to-one functions (the restricted domain ensures this), and (iv) involves routine inverse function manipulation. All parts are textbook-standard with no novel insight required, making it slightly easier than average.
Spec1.02v Inverse and composite functions: graphs and conditions for existence1.05f Trigonometric function graphs: symmetries and periodicities1.05o Trigonometric equations: solve in given intervals

The function \(\text{f} : x \mapsto 5 + 3\cos(\frac{1}{3}x)\) is defined for \(0 \leqslant x \leqslant 2\pi\).
  1. Solve the equation \(\text{f}(x) = 7\), giving your answer correct to 2 decimal places. [3]
  2. Sketch the graph of \(y = \text{f}(x)\). [2]
  3. Explain why \(\text{f}\) has an inverse. [1]
  4. Obtain an expression for \(\text{f}^{-1}(x)\). [3]

The function $\text{f} : x \mapsto 5 + 3\cos(\frac{1}{3}x)$ is defined for $0 \leqslant x \leqslant 2\pi$.

\begin{enumerate}[label=(\roman*)]
\item Solve the equation $\text{f}(x) = 7$, giving your answer correct to 2 decimal places. [3]
\item Sketch the graph of $y = \text{f}(x)$. [2]
\item Explain why $\text{f}$ has an inverse. [1]
\item Obtain an expression for $\text{f}^{-1}(x)$. [3]
\end{enumerate}

\hfill \mbox{\textit{CAIE P1 2015 Q8 [9]}}