WJEC Unit 3 2019 June — Question 15

Exam BoardWJEC
ModuleUnit 3 (Unit 3)
Year2019
SessionJune
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicProof
TypeContradiction proof of irrationality
DifficultyStandard +0.3 This is a standard proof by contradiction following the classic template for proving √n is irrational (assume √6 = p/q in lowest terms, square both sides, show p² is divisible by 6 hence p is divisible by 6, substitute to show q² is also divisible by 6, contradiction). While it requires understanding proof structure, it's a direct application of a well-rehearsed technique with no novel insight needed, making it slightly easier than average.
Spec1.01d Proof by contradiction

Use proof by contradiction to show that \(\sqrt { 6 }\) is irrational.

Use proof by contradiction to show that $\sqrt { 6 }$ is irrational.

\hfill \mbox{\textit{WJEC Unit 3 2019 Q15}}