Pre-U Pre-U 9794/2 2019 Specimen — Question 10 12 marks

Exam BoardPre-U
ModulePre-U 9794/2 (Pre-U Mathematics Paper 2)
Year2019
SessionSpecimen
Marks12
TopicDifferentiating Transcendental Functions
TypeSolve equation involving derivatives
DifficultyStandard +0.8 Part (a) is a standard product rule differentiation with transcendental functions requiring setting dy/dx=0 and algebraic manipulation—routine A-level technique. Part (b) requires evaluating two models against experimental data by substituting coordinates and checking consistency, involving some calculation but straightforward application. The multi-part structure and model evaluation adds modest complexity beyond typical textbook exercises, but no novel mathematical insight is required.
Spec1.05k Further identities: sec^2=1+tan^2 and cosec^2=1+cot^21.06a Exponential function: a^x and e^x graphs and properties1.07q Product and quotient rules: differentiation1.07r Chain rule: dy/dx = dy/du * du/dx and connected rates

10 A curve has equation $$y = \mathrm { e } ^ { a x } \cos b x$$ where \(a\) and \(b\) are constants.
  1. Show that, at any stationary points on the curve, \(\tan b x = \frac { a } { b }\).
  2. \includegraphics[max width=\textwidth, alt={}, center]{48b63de9-f022-4881-a187-f08e3c7d9f1a-4_620_894_1064_342} Values of related quantities \(x\) and \(y\) were measured in an experiment and plotted on a graph of \(y\) against \(x\), as shown in the diagram. Two of the points, labelled \(A\) and \(B\), have coordinates \(( 0,1 )\) and \(( 0.2 , - 0.8 )\) respectively. A third point labelled \(C\) has coordinates ( \(0.3,0.04\) ). Attempts were then made to find the equation of a curve which fitted closely to these three points, and two models were proposed. In the first model the equation is \(y = \mathrm { e } ^ { - x } \cos 15 x\). In the second model the equation is \(y = f \cos ( \lambda x ) + g\), where the constants \(f , \lambda\), and \(g\) are chosen to give a maximum precisely at the point \(A ( 0,1 )\) and a minimum precisely at the point \(B ( 0.2 , - 0.8 )\). By calculating suitable values evaluate the suitability of the two models.

(a)
Attempt to use product rule — M1
\(y' = ae^{ax}\cos bx - be^{ax}\sin bx\) — A1
Set \(y' = 0\) and rearrange — M1
\(\tan bx = \frac{a}{b}\) validly obtained — A1 [4]
(b)
Model 1: Correct method to solve \(\tan 15x = -\frac{1}{15} \Rightarrow x = -0.00444...\) — M1
Obtain \(y = 1.0022\) — A1
Correct method to solve \(x + \frac{\pi}{15} = 0.20499\) — M1
Obtain \(y = -0.81284\) — A1
State when \(x = 0.3\), \(y = -0.156\) — B1
Model 2: Obtain \(f + g = 1\) — B1
Obtain \(-f + g = -0.8\) — B1
Attempt to solve their equations simultaneously — M1
Obtain \(f = 0.9\), \(g = 0.1\) — A1
Obtain \(\lambda = 5\pi\) — B1
State when \(x = 0.3\), \(y = 0.1\) — B1
Relevant comment that model 2 matches experimental data more closely — B1 [12]
**(a)**
Attempt to use product rule — **M1**
$y' = ae^{ax}\cos bx - be^{ax}\sin bx$ — **A1**
Set $y' = 0$ and rearrange — **M1**
$\tan bx = \frac{a}{b}$ validly obtained — **A1** [4]

**(b)**
**Model 1:** Correct method to solve $\tan 15x = -\frac{1}{15} \Rightarrow x = -0.00444...$ — **M1**
Obtain $y = 1.0022$ — **A1**
Correct method to solve $x + \frac{\pi}{15} = 0.20499$ — **M1**
Obtain $y = -0.81284$ — **A1**
State when $x = 0.3$, $y = -0.156$ — **B1**

**Model 2:** Obtain $f + g = 1$ — **B1**
Obtain $-f + g = -0.8$ — **B1**
Attempt to solve their equations simultaneously — **M1**
Obtain $f = 0.9$, $g = 0.1$ — **A1**
Obtain $\lambda = 5\pi$ — **B1**
State when $x = 0.3$, $y = 0.1$ — **B1**
Relevant comment that model 2 matches experimental data more closely — **B1** [12]
10 A curve has equation

$$y = \mathrm { e } ^ { a x } \cos b x$$

where $a$ and $b$ are constants.
\begin{enumerate}[label=(\alph*)]
\item Show that, at any stationary points on the curve, $\tan b x = \frac { a } { b }$.
\item \\
\includegraphics[max width=\textwidth, alt={}, center]{48b63de9-f022-4881-a187-f08e3c7d9f1a-4_620_894_1064_342}

Values of related quantities $x$ and $y$ were measured in an experiment and plotted on a graph of $y$ against $x$, as shown in the diagram. Two of the points, labelled $A$ and $B$, have coordinates $( 0,1 )$ and $( 0.2 , - 0.8 )$ respectively. A third point labelled $C$ has coordinates ( $0.3,0.04$ ). Attempts were then made to find the equation of a curve which fitted closely to these three points, and two models were proposed.

In the first model the equation is $y = \mathrm { e } ^ { - x } \cos 15 x$.

In the second model the equation is $y = f \cos ( \lambda x ) + g$, where the constants $f , \lambda$, and $g$ are chosen to give a maximum precisely at the point $A ( 0,1 )$ and a minimum precisely at the point $B ( 0.2 , - 0.8 )$.

By calculating suitable values evaluate the suitability of the two models.

\end{enumerate}

\hfill \mbox{\textit{Pre-U Pre-U 9794/2 2019 Q10 [12]}}