Pre-U Pre-U 9794/1 2019 Specimen — Question 4 1 marks

Exam BoardPre-U
ModulePre-U 9794/1 (Pre-U Mathematics Paper 1)
Year2019
SessionSpecimen
Marks1
TopicFactor & Remainder Theorem
TypeFully specified polynomial: verify factor and solve
DifficultyModerate -0.8 This is a straightforward application of the factor theorem requiring substitution to verify x=2 is a root, then polynomial division to find the quadratic factor, followed by solving a simple quadratic. All steps are routine with no problem-solving insight needed, making it easier than average but not trivial since it requires multiple standard techniques.
Spec1.02j Manipulate polynomials: expanding, factorising, division, factor theorem

4
  1. Show that \(x = 2\) is a root of the equation \(2 x ^ { 3 } - x ^ { 2 } - 15 x + 18 = 0\).
  2. Hence solve the equation \(2 x ^ { 3 } - x ^ { 2 } - 15 x + 18 = 0\).

(a) \(\text{f}(-2) = 0\) clearly shown — B1
Total: 1
(b) Method shown e.g. division — M1
Obtain \(2x^2 + 3x - 9\) — A1
Attempt to solve quadratic \(((2x-3)(x+3))\) — M1
\(x = \frac{3}{2}\) — B1 (B1ft)
\(x = 2\) and \(x = -3\) — B1 (B1ft)
Total: 5
(a) $\text{f}(-2) = 0$ clearly shown — **B1**
**Total: 1**

(b) Method shown e.g. division — **M1**
Obtain $2x^2 + 3x - 9$ — **A1**
Attempt to solve quadratic $((2x-3)(x+3))$ — **M1**
$x = \frac{3}{2}$ — **B1** (B1ft)
$x = 2$ and $x = -3$ — **B1** (B1ft)
**Total: 5**
4
\begin{enumerate}[label=(\alph*)]
\item Show that $x = 2$ is a root of the equation $2 x ^ { 3 } - x ^ { 2 } - 15 x + 18 = 0$.
\item Hence solve the equation $2 x ^ { 3 } - x ^ { 2 } - 15 x + 18 = 0$.
\end{enumerate}

\hfill \mbox{\textit{Pre-U Pre-U 9794/1 2019 Q4 [1]}}