Pre-U Pre-U 9795/1 2016 Specimen — Question 11 11 marks

Exam BoardPre-U
ModulePre-U 9795/1 (Pre-U Further Mathematics Paper 1)
Year2016
SessionSpecimen
Marks11
TopicComplex numbers 2
TypeExpress roots in trigonometric form
DifficultyChallenging +1.8 This is a substantial multi-part question requiring de Moivre's theorem for deriving a trigonometric identity, deducing an exact value, finding fifth roots in polar form, and calculating a pentagon area. While each component uses standard Further Maths techniques, the combination of proof, algebraic manipulation to extract sin(2π/5), and geometric calculation with exact surds makes this significantly harder than average A-level questions but not exceptionally difficult for Further Maths students.
Spec1.05m Geometric proofs: of trig sum and double angle formulae4.02k Argand diagrams: geometric interpretation4.02q De Moivre's theorem: multiple angle formulae4.02r nth roots: of complex numbers

11
  1. Use de Moivre's theorem to prove that \(\sin 5 \theta \equiv s \left( 16 s ^ { 4 } - 20 s ^ { 2 } + 5 \right)\), where \(s = \sin \theta\), and deduce that $$\sin \frac { 2 \pi } { 5 } = \sqrt { \frac { 5 + \sqrt { 5 } } { 8 } }$$ The complex number \(\omega = 16 ( - 1 + \mathrm { i } \sqrt { 3 } )\).
  2. State the value of \(| \omega |\) and find \(\arg \omega\) as a rational multiple of \(\pi\).
  3. (a) Determine the five roots of the equation \(z ^ { 5 } = \omega\), giving your answers in the form ( \(\mathrm { r } , \theta\) ), where \(r > 0\) and \(- \pi < \theta \leqslant \pi\).
    (b) These five roots are represented in the complex plane by the points \(A , B , C , D\) and \(E\). Show these points on an Argand diagram, and find the area of the pentagon \(A B C D E\) in an exact surd form.

(i) \(\frac{\mathrm{d}y}{\mathrm{d}x}+y=3xy^4\) is a Bernoulli (differential) equation
\(u=\frac{1}{y^3} \Rightarrow \frac{\mathrm{d}u}{\mathrm{d}x}=-\frac{3}{y^4}\times\frac{\mathrm{d}y}{\mathrm{d}x}\) B1
Then \(\frac{\mathrm{d}y}{\mathrm{d}x}+y=3xy^4\) becomes \(-\frac{3}{y^4}\frac{\mathrm{d}y}{\mathrm{d}x}-\frac{3}{y^3}=-9x \Rightarrow \frac{\mathrm{d}u}{\mathrm{d}x}-3u=-9x\) AG M1 A1
(ii) Method 1:
IF is \(\mathrm{e}^{-3x}\) M1 A1
\(\Rightarrow u\mathrm{e}^{-3x}=\int -9x\mathrm{e}^{-3x}\,\mathrm{d}x\) M1
\(=3x\mathrm{e}^{-3x}-\int 3\mathrm{e}^{-3x}\,\mathrm{d}x\) — Use of "parts" M1
\(=(3x+1)\mathrm{e}^{-3x}+C\) A1
General solution: \(u=3x+1+C\mathrm{e}^{3x}\) ft B1
\(\Rightarrow y^{-3}=\frac{1}{3x+1+C\mathrm{e}^{3x}}\) ft B1
Using \(x=0\), \(y=\frac{1}{2}\) to find \(C\): \(C=7\) or \(y^3=\frac{1}{3x+1+7\mathrm{e}^{3x}}\) M1 A1
Method 2:
Auxiliary equation \(m-3=0 \Rightarrow u_C=A\mathrm{e}^{3x}\) is the complementary function M1 A1
For particular integral try \(u_P=ax+b\), \(u_P'=a\) M1
Substituting \(u_P=ax+b\) and \(u_P'=a\) into the d.e. and comparing terms M1
\(a-3ax-3b=-9x \Rightarrow a=3,\,b=1\) i.e. \(u_P=3x+1\) A1
General solution: \(u=3x+1+A\mathrm{e}^{3x}\) ft B1
\(\Rightarrow y^{-3}=\frac{1}{3x+1+A\mathrm{e}^{3x}}\) ft B1
Using \(x=0\), \(y=\frac{1}{2}\) to find \(A\): \(A=7\) or \(y^3=\frac{1}{3x+1+7\mathrm{e}^{3x}}\) M1 A1
Total: 11 marks
**(i)** $\frac{\mathrm{d}y}{\mathrm{d}x}+y=3xy^4$ is a Bernoulli (differential) equation

$u=\frac{1}{y^3} \Rightarrow \frac{\mathrm{d}u}{\mathrm{d}x}=-\frac{3}{y^4}\times\frac{\mathrm{d}y}{\mathrm{d}x}$ **B1**

Then $\frac{\mathrm{d}y}{\mathrm{d}x}+y=3xy^4$ becomes $-\frac{3}{y^4}\frac{\mathrm{d}y}{\mathrm{d}x}-\frac{3}{y^3}=-9x \Rightarrow \frac{\mathrm{d}u}{\mathrm{d}x}-3u=-9x$ **AG** **M1 A1**

**(ii) Method 1:**

IF is $\mathrm{e}^{-3x}$ **M1 A1**

$\Rightarrow u\mathrm{e}^{-3x}=\int -9x\mathrm{e}^{-3x}\,\mathrm{d}x$ **M1**

$=3x\mathrm{e}^{-3x}-\int 3\mathrm{e}^{-3x}\,\mathrm{d}x$ — Use of "parts" **M1**

$=(3x+1)\mathrm{e}^{-3x}+C$ **A1**

General solution: $u=3x+1+C\mathrm{e}^{3x}$ **ft** **B1**

$\Rightarrow y^{-3}=\frac{1}{3x+1+C\mathrm{e}^{3x}}$ **ft** **B1**

Using $x=0$, $y=\frac{1}{2}$ to find $C$: $C=7$ or $y^3=\frac{1}{3x+1+7\mathrm{e}^{3x}}$ **M1 A1**

**Method 2:**

Auxiliary equation $m-3=0 \Rightarrow u_C=A\mathrm{e}^{3x}$ is the complementary function **M1 A1**

For particular integral try $u_P=ax+b$, $u_P'=a$ **M1**

Substituting $u_P=ax+b$ and $u_P'=a$ into the d.e. and comparing terms **M1**

$a-3ax-3b=-9x \Rightarrow a=3,\,b=1$ i.e. $u_P=3x+1$ **A1**

General solution: $u=3x+1+A\mathrm{e}^{3x}$ **ft** **B1**

$\Rightarrow y^{-3}=\frac{1}{3x+1+A\mathrm{e}^{3x}}$ **ft** **B1**

Using $x=0$, $y=\frac{1}{2}$ to find $A$: $A=7$ or $y^3=\frac{1}{3x+1+7\mathrm{e}^{3x}}$ **M1 A1**

**Total: 11 marks**
11
\begin{enumerate}[label=(\roman*)]
\item Use de Moivre's theorem to prove that $\sin 5 \theta \equiv s \left( 16 s ^ { 4 } - 20 s ^ { 2 } + 5 \right)$, where $s = \sin \theta$, and deduce that

$$\sin \frac { 2 \pi } { 5 } = \sqrt { \frac { 5 + \sqrt { 5 } } { 8 } }$$

The complex number $\omega = 16 ( - 1 + \mathrm { i } \sqrt { 3 } )$.
\item State the value of $| \omega |$ and find $\arg \omega$ as a rational multiple of $\pi$.
\item (a) Determine the five roots of the equation $z ^ { 5 } = \omega$, giving your answers in the form ( $\mathrm { r } , \theta$ ), where $r > 0$ and $- \pi < \theta \leqslant \pi$.\\
(b) These five roots are represented in the complex plane by the points $A , B , C , D$ and $E$. Show these points on an Argand diagram, and find the area of the pentagon $A B C D E$ in an exact surd form.
\end{enumerate}

\hfill \mbox{\textit{Pre-U Pre-U 9795/1 2016 Q11 [11]}}