Pre-U Pre-U 9794/3 2016 Specimen — Question 7 6 marks

Exam BoardPre-U
ModulePre-U 9794/3 (Pre-U Mathematics Paper 3)
Year2016
SessionSpecimen
Marks6
TopicVariable acceleration (1D)
TypeFinding when particle at rest
DifficultyModerate -0.3 This is a straightforward mechanics question requiring factorization of a cubic to find when v=0, and integration of velocity to find displacement. Both are standard A-level techniques with no conceptual challenges—slightly easier than average due to the clean factorization and routine calculus.
Spec1.08d Evaluate definite integrals: between limits3.02a Kinematics language: position, displacement, velocity, acceleration3.02f Non-uniform acceleration: using differentiation and integration

7 A particle travels along a straight line. Its velocity \(v \mathrm {~ms} ^ { - 1 }\) after \(t\) seconds is given by $$v = t ^ { 3 } - 9 t ^ { 2 } + 20 t$$ When \(t = 0\), the particle is at rest at \(P\).
  1. Find the times, other than \(t = 0\), at which the particle is at rest.
  2. Find the displacement of the particle from \(P\) when \(t = 2\).

Question 7
(i) \(v = t(t-4)(t-5)\) [M1]
\(t = 4\) and \(5\) [A1]
(ii) \(x = \frac{t^4}{4} - 3t^3 + 10t^2 + c\) [M1]
All terms correct including "\(+ c\)" [A1]
When \(x = 0\), \(t = 0\) therefore \(c = 0\) [A1]
When \(t = 2\), \(x = 4 - 24 + 40 = 20\) [A1]
Total: 6 marks
**Question 7**

(i) $v = t(t-4)(t-5)$ [M1]

$t = 4$ and $5$ [A1]

(ii) $x = \frac{t^4}{4} - 3t^3 + 10t^2 + c$ [M1]

All terms correct including "$+ c$" [A1]

When $x = 0$, $t = 0$ therefore $c = 0$ [A1]

When $t = 2$, $x = 4 - 24 + 40 = 20$ [A1]

**Total: 6 marks**
7 A particle travels along a straight line. Its velocity $v \mathrm {~ms} ^ { - 1 }$ after $t$ seconds is given by

$$v = t ^ { 3 } - 9 t ^ { 2 } + 20 t$$

When $t = 0$, the particle is at rest at $P$.\\
(i) Find the times, other than $t = 0$, at which the particle is at rest.\\
(ii) Find the displacement of the particle from $P$ when $t = 2$.

\hfill \mbox{\textit{Pre-U Pre-U 9794/3 2016 Q7 [6]}}