Pre-U Pre-U 9794/3 2016 Specimen — Question 5 11 marks

Exam BoardPre-U
ModulePre-U 9794/3 (Pre-U Mathematics Paper 3)
Year2016
SessionSpecimen
Marks11
TopicDiscrete Probability Distributions
TypeConstruct probability distribution from scenario
DifficultyModerate -0.8 This is a straightforward probability distribution question requiring basic understanding of net gain/loss, expected value calculation (formula given), and binomial probability. The multi-part structure and 10-mark allocation are typical, but each step involves standard textbook techniques with no novel insight or complex reasoning required.
Spec2.04a Discrete probability distributions2.04b Binomial distribution: as model B(n,p)2.04e Normal distribution: as model N(mu, sigma^2)2.04h Select appropriate distribution

5 James plays an arcade game. Each time he plays, he puts a \(\pounds 1\) coin in the slot to start the game. The possible outcomes of each game are as follows: James loses the game with a probability of 0.7 and the machine pays out nothing, James draws the game with a probability of 0.25 and the machine pays out a \(\pounds 1\) coin, James wins the game with a probability of 0.05 and the machine pays out ten \(\pounds 1\) coins. The outcomes can be modelled by a random variable \(X\) representing the number of \(\pounds 1\) coins gained at the end of a game.
  1. Construct a probability distribution table for \(X\).
  2. Show that \(\mathrm { E } ( X ) = - 0.25\) and find \(\operatorname { Var } ( X )\). James starts off with \(10 \pounds 1\) coins and decides to play exactly 10 games.
  3. Find the expected number of \(\pounds 1\) coins that James will have at the end of his 10 games.
  4. Find the probability that after his 10 games James will have at least \(10 \pounds 1\) coins left.

Question 5
(i) Table shows \((-1, 0.7)\) [B1]
\((0, 0.25)\) and \((9, 0.05)\) [B1]
(ii) Use \(E(X)\) formula [M1]
Obtain \(-0.25\) AG [A1]
Use \(E(X^2)\) formula [M1]
Obtain \(4.6875\) (or \(4.69\)) o.e. [A1]
(iii) Use \(10 + 10E(X)\) [M1]
Obtain \(10 + 10(-0.25) = 7.5\) [A1]
(iv) P(Must win at least one game) [M1]
States \((0.25)^{10}\) [B1]
Obtain \(1 - (0.95)^{10} + (0.25)^{10} = 0.401\) [A1]
Total: 11 marks
**Question 5**

(i) Table shows $(-1, 0.7)$ [B1]

$(0, 0.25)$ and $(9, 0.05)$ [B1]

(ii) Use $E(X)$ formula [M1]

Obtain $-0.25$ AG [A1]

Use $E(X^2)$ formula [M1]

Obtain $4.6875$ (or $4.69$) o.e. [A1]

(iii) Use $10 + 10E(X)$ [M1]

Obtain $10 + 10(-0.25) = 7.5$ [A1]

(iv) P(Must win at least one game) [M1]

States $(0.25)^{10}$ [B1]

Obtain $1 - (0.95)^{10} + (0.25)^{10} = 0.401$ [A1]

**Total: 11 marks**
5 James plays an arcade game. Each time he plays, he puts a $\pounds 1$ coin in the slot to start the game. The possible outcomes of each game are as follows:

James loses the game with a probability of 0.7 and the machine pays out nothing, James draws the game with a probability of 0.25 and the machine pays out a $\pounds 1$ coin, James wins the game with a probability of 0.05 and the machine pays out ten $\pounds 1$ coins.

The outcomes can be modelled by a random variable $X$ representing the number of $\pounds 1$ coins gained at the end of a game.\\
(i) Construct a probability distribution table for $X$.\\
(ii) Show that $\mathrm { E } ( X ) = - 0.25$ and find $\operatorname { Var } ( X )$.

James starts off with $10 \pounds 1$ coins and decides to play exactly 10 games.\\
(iii) Find the expected number of $\pounds 1$ coins that James will have at the end of his 10 games.\\
(iv) Find the probability that after his 10 games James will have at least $10 \pounds 1$ coins left.

\hfill \mbox{\textit{Pre-U Pre-U 9794/3 2016 Q5 [11]}}