CAIE P1 2006 June — Question 3 5 marks

Exam BoardCAIE
ModuleP1 (Pure Mathematics 1)
Year2006
SessionJune
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicGeometric Sequences and Series
TypeCompound growth applications
DifficultyEasy -1.2 This is a straightforward application of geometric sequences requiring only direct substitution into standard formulas (nth term and sum of GP). The 5% growth rate immediately gives r=1.05, and both parts involve routine calculations with no problem-solving insight needed—significantly easier than average A-level questions.
Spec1.04i Geometric sequences: nth term and finite series sum1.04k Modelling with sequences: compound interest, growth/decay

3 Each year a company gives a grant to a charity. The amount given each year increases by \(5 \%\) of its value in the preceding year. The grant in 2001 was \(\\) 5000$. Find
  1. the grant given in 2011,
  2. the total amount of money given to the charity during the years 2001 to 2011 inclusive.

AnswerMarks Guidance
(i) \(r = 1.05\) with GP, 2011 is 11 years. Uses \(ar^{n-1}\) → \(\\)8144\( (or 8140)B1 M1 A1 Anywhere in the question. This could be marked as \)2 + 3\(. Allow if correct formula with \)n = 10$ co. (allow 3 sf)
(ii) Use of \(S_n\) formula → \(\\)71034$M1 A1 Allow if used correctly with 10 or 11. co. (or 71 000)
Total: [3] [2]
**(i)** $r = 1.05$ with GP, 2011 is 11 years. Uses $ar^{n-1}$ → $\$8144$ (or 8140) | B1 M1 A1 | Anywhere in the question. This could be marked as $2 + 3$. Allow if correct formula with $n = 10$ co. (allow 3 sf)

**(ii)** Use of $S_n$ formula → $\$71034$ | M1 A1 | Allow if used correctly with 10 or 11. co. (or 71 000)

**Total: [3] [2]**

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3 Each year a company gives a grant to a charity. The amount given each year increases by $5 \%$ of its value in the preceding year. The grant in 2001 was $\$ 5000$. Find\\
(i) the grant given in 2011,\\
(ii) the total amount of money given to the charity during the years 2001 to 2011 inclusive.

\hfill \mbox{\textit{CAIE P1 2006 Q3 [5]}}