Pre-U Pre-U 9794/1 2015 June — Question 11 10 marks

Exam BoardPre-U
ModulePre-U 9794/1 (Pre-U Mathematics Paper 1)
Year2015
SessionJune
Marks10
TopicIntegration by Substitution
TypeIndefinite integral with non-linear substitution (algebraic/exponential/logarithmic)
DifficultyStandard +0.8 This is a challenging integration by substitution problem requiring multiple steps: applying the given substitution x = u² - 1, simplifying the resulting integral (likely involving partial fractions or logarithmic forms), and then substituting back to reach the specific form with nested radicals. The algebraic manipulation to achieve the exact form given, particularly with the nested square roots and the ratio structure, is non-trivial and goes beyond routine substitution exercises. However, it's guided by the suggested substitution and is a standard Pre-U/Further Maths technique rather than requiring novel insight.
Spec1.08h Integration by substitution

11 Using the substitution \(x = u ^ { 2 } - 1\), or otherwise, show that $$\int \frac { 1 } { 2 x \sqrt { x + 1 } } \mathrm {~d} x = \ln \left( A \sqrt { \frac { \sqrt { x + 1 } - 1 } { \sqrt { x + 1 } + 1 } } \right)$$ where \(A\) is an arbitrary constant and \(x > 0\).

Obtain \(\mathrm{d}x = f(u)\,\mathrm{d}u\) or equivalent [B1]
Rewrite \(\sqrt{x+1}\) in terms of \(u\) and substitute to obtain an integral in \(u\) [M1]
Obtain unsimplified \(\displaystyle\int \frac{2u\,\mathrm{d}u}{2(u^2-1)\sqrt{(u^2-1)+1}}\) [A1]
Obtain \(\displaystyle\int \frac{\mathrm{d}u}{u^2-1}\) [A1]
Use partial fractions in form \(\dfrac{A}{u+1} + \dfrac{B}{u-1}\) [M1]
Obtain \(A = -\dfrac{1}{2}\) and \(B = \dfrac{1}{2}\) both correctly placed [A1]
AnswerMarks Guidance
Integrate to obtain \(\left(k\lnu-1 + m\ln
Obtain \(\dfrac{1}{2}\ln(u-1) - \dfrac{1}{2}\ln(u+1) = c\) or \(\dfrac{1}{2}\ln\left(\dfrac{u-1}{u+1}\right) + c\) [A1]
Show correct use of at least one log law on a correct equation [M1]
State or show clearly \(+ c = \ln A\) and obtain \(\ln\left(A\sqrt{\dfrac{\sqrt{x+1}-1}{\sqrt{x+1}+1}}\right)\) AG [A1]
Total: [10]
Obtain $\mathrm{d}x = f(u)\,\mathrm{d}u$ or equivalent [B1]
Rewrite $\sqrt{x+1}$ in terms of $u$ and substitute to obtain an integral in $u$ [M1]
Obtain unsimplified $\displaystyle\int \frac{2u\,\mathrm{d}u}{2(u^2-1)\sqrt{(u^2-1)+1}}$ [A1]
Obtain $\displaystyle\int \frac{\mathrm{d}u}{u^2-1}$ [A1]
Use partial fractions in form $\dfrac{A}{u+1} + \dfrac{B}{u-1}$ [M1]
Obtain $A = -\dfrac{1}{2}$ and $B = \dfrac{1}{2}$ both correctly placed [A1]
Integrate to obtain $\left(k\ln|u-1| + m\ln|u+1|\right)$ [M1]
Obtain $\dfrac{1}{2}\ln(u-1) - \dfrac{1}{2}\ln(u+1) = c$ or $\dfrac{1}{2}\ln\left(\dfrac{u-1}{u+1}\right) + c$ [A1]
Show correct use of at least one log law on a correct equation [M1]
State or show clearly $+ c = \ln A$ **and** obtain $\ln\left(A\sqrt{\dfrac{\sqrt{x+1}-1}{\sqrt{x+1}+1}}\right)$ **AG** [A1]
**Total: [10]**
11 Using the substitution $x = u ^ { 2 } - 1$, or otherwise, show that

$$\int \frac { 1 } { 2 x \sqrt { x + 1 } } \mathrm {~d} x = \ln \left( A \sqrt { \frac { \sqrt { x + 1 } - 1 } { \sqrt { x + 1 } + 1 } } \right)$$

where $A$ is an arbitrary constant and $x > 0$.

\hfill \mbox{\textit{Pre-U Pre-U 9794/1 2015 Q11 [10]}}