Pre-U Pre-U 9795/1 2014 June — Question 2 8 marks

Exam BoardPre-U
ModulePre-U 9795/1 (Pre-U Further Mathematics Paper 1)
Year2014
SessionJune
Marks8
Topic3x3 Matrices
TypeInverse given/derived then solve system
DifficultyStandard +0.3 This is a structured multi-part question that guides students through finding a parameter value, setting up a matrix equation, and using matrix inverses to solve a system. While it involves 3×3 matrices (which are computationally heavier than 2×2), the question provides clear scaffolding and the connection between parts makes it easier than average. The matrix multiplication in part (i) is routine but tedious, and recognizing that C = B^T in part (ii) requires some observation, but overall this is a standard Further Maths exercise with no novel insights required.
Spec4.03b Matrix operations: addition, multiplication, scalar4.03c Matrix multiplication: properties (associative, not commutative)4.03o Inverse 3x3 matrix4.03r Solve simultaneous equations: using inverse matrix

2
  1. Show that there is a value of \(t\) for which \(\mathbf { A B }\) is an integer multiple of the \(3 \times 3\) identity matrix \(\mathbf { I }\), where $$\mathbf { A } = \left( \begin{array} { r r r } 1 & 2 & 1 \\ t & 1 & - t \\ 3 & 2 & 1 \end{array} \right) \quad \text { and } \quad \mathbf { B } = \left( \begin{array} { c r r } t - 2 & 0 & 5 \\ 12 & - 2 & - 6 \\ 3 t & 4 & 7 \end{array} \right) .$$
  2. Express the system of equations $$\begin{aligned} - 5 x + 5 z & = 8 \\ 12 x - 2 y - 6 z & = 12 \\ - 9 x + 4 y + 7 z & = 22 \end{aligned}$$ in the form \(\mathbf { C x } = \mathbf { u }\), where \(\mathbf { C }\) is a \(3 \times 3\) matrix, and \(\mathbf { x }\) and \(\mathbf { u }\) are suitable column vectors.
  3. Use the result of part (i) to solve the system of equations given in part (ii).

(i) \(\mathbf{AB} = \begin{bmatrix} 1 & 2 & 1 \\ t & 1 & -t \\ 3 & 2 & 1 \end{bmatrix}\begin{bmatrix} t-2 & 0 & 5 \\ 12 & -2 & -6 \\ 3t & 4 & 7 \end{bmatrix} = \begin{bmatrix} 4t+22 & 0 & 0 \\ 12-2t-2t^2 & -2-4t & -2t-6 \\ 6t+18 & 0 & 10 \end{bmatrix}\) M1
M1 good effort; A1 all correct A1
Give M0 (A0) B1 B1 for BA found (\(k\), \(t\) \(\checkmark\)) or \(k\), \(t\) found from 1 or 2 elements of AB only
Give M1 (A0) B1 B1 for \(k\), \(t\) found from most (but not all) elements of AB
\(= 10\mathbf{I}\) when \(t = -3\) Allow these correct from most of AB correct A1 A1 [4]
(ii) \(\begin{bmatrix} -5 & 0 & 5 \\ 12 & -2 & -6 \\ -9 & 4 & 7 \end{bmatrix}\begin{bmatrix} x \\ y \\ z \end{bmatrix} = \begin{bmatrix} 8 \\ 12 \\ 22 \end{bmatrix}\) B1 [1]
(iii) \(\begin{bmatrix} x \\ y \\ z \end{bmatrix} = \frac{1}{10}\begin{bmatrix} 1 & 2 & 1 \\ -3 & 1 & 3 \\ 3 & 2 & 1 \end{bmatrix}\begin{bmatrix} 8 \\ 12 \\ 22 \end{bmatrix}\) M1 for \(\mathbf{x} = C^{-1}\mathbf{u}\) B1 for \(C^{-1}\) correct M1 B1
\(x = 5.4,\ y = 5.4,\ z = 7\) A1 [3]
B1 SC for correct \(x\), \(y\), \(z\) without inverse matrix method seen
(i) $\mathbf{AB} = \begin{bmatrix} 1 & 2 & 1 \\ t & 1 & -t \\ 3 & 2 & 1 \end{bmatrix}\begin{bmatrix} t-2 & 0 & 5 \\ 12 & -2 & -6 \\ 3t & 4 & 7 \end{bmatrix} = \begin{bmatrix} 4t+22 & 0 & 0 \\ 12-2t-2t^2 & -2-4t & -2t-6 \\ 6t+18 & 0 & 10 \end{bmatrix}$ **M1**

M1 good effort; A1 all correct **A1**

Give M0 (A0) B1 B1 for **BA** found ($k$, $t$ $\checkmark$) or $k$, $t$ found from 1 or 2 elements of **AB** only
Give M1 (A0) B1 B1 for $k$, $t$ found from most (but not all) elements of **AB**

$= 10\mathbf{I}$ when $t = -3$ Allow these correct from most of **AB** correct **A1 A1** [4]

(ii) $\begin{bmatrix} -5 & 0 & 5 \\ 12 & -2 & -6 \\ -9 & 4 & 7 \end{bmatrix}\begin{bmatrix} x \\ y \\ z \end{bmatrix} = \begin{bmatrix} 8 \\ 12 \\ 22 \end{bmatrix}$ **B1** [1]

(iii) $\begin{bmatrix} x \\ y \\ z \end{bmatrix} = \frac{1}{10}\begin{bmatrix} 1 & 2 & 1 \\ -3 & 1 & 3 \\ 3 & 2 & 1 \end{bmatrix}\begin{bmatrix} 8 \\ 12 \\ 22 \end{bmatrix}$ M1 for $\mathbf{x} = C^{-1}\mathbf{u}$ B1 for $C^{-1}$ correct **M1 B1**

$x = 5.4,\ y = 5.4,\ z = 7$ **A1** [3]

**B1** SC for correct $x$, $y$, $z$ without inverse matrix method seen
2 (i) Show that there is a value of $t$ for which $\mathbf { A B }$ is an integer multiple of the $3 \times 3$ identity matrix $\mathbf { I }$, where

$$\mathbf { A } = \left( \begin{array} { r r r } 
1 & 2 & 1 \\
t & 1 & - t \\
3 & 2 & 1
\end{array} \right) \quad \text { and } \quad \mathbf { B } = \left( \begin{array} { c r r } 
t - 2 & 0 & 5 \\
12 & - 2 & - 6 \\
3 t & 4 & 7
\end{array} \right) .$$

(ii) Express the system of equations

$$\begin{aligned}
- 5 x + 5 z & = 8 \\
12 x - 2 y - 6 z & = 12 \\
- 9 x + 4 y + 7 z & = 22
\end{aligned}$$

in the form $\mathbf { C x } = \mathbf { u }$, where $\mathbf { C }$ is a $3 \times 3$ matrix, and $\mathbf { x }$ and $\mathbf { u }$ are suitable column vectors.\\
(iii) Use the result of part (i) to solve the system of equations given in part (ii).

\hfill \mbox{\textit{Pre-U Pre-U 9795/1 2014 Q2 [8]}}