Pre-U Pre-U 9795/2 2013 June — Question 5 8 marks

Exam BoardPre-U
ModulePre-U 9795/2 (Pre-U Further Mathematics Paper 2)
Year2013
SessionJune
Marks8
TopicProbability Generating Functions
TypeDetermine constant in PGF
DifficultyStandard +0.3 This is a straightforward PGF question requiring standard techniques: finding k using G(1)=1, identifying the modal value from coefficients, using the independence property for sums, and applying G'(1) and G''(1) formulas for mean and variance. All steps are routine applications of PGF theory with no novel problem-solving required, making it slightly easier than average.
Spec5.03a Continuous random variables: pdf and cdf5.04a Linear combinations: E(aX+bY), Var(aX+bY)

5 The discrete random variable \(X\) has probability generating function given by $$\mathrm { G } _ { X } ( t ) = k \left( 5 t ^ { - 1 } + 3 + 2 t ^ { 2 } \right) ,$$ where \(k\) is a constant.
  1. Find
    1. the value of \(k\),
    2. the modal value of \(X\).
    3. The random variables \(X _ { 1 }\) and \(X _ { 2 }\) are independent observations of \(X\).
      (a) Write down the probability generating function of \(Y\), where \(Y = X _ { 1 } + X _ { 2 }\).
      (b) Use your answer to part (ii)(a) to find \(\mathrm { E } ( Y )\) and \(\operatorname { Var } ( Y )\).

(i)(a) \(k(5 + 3 + 2) = 1 \Rightarrow k = \frac{1}{10}\) B1 [1]
(i)(b) Modal value is \(-1\). B1 [1]
(ii)(a) \(G_Y(t) = \frac{1}{100}(5t^{-1} + 3 + 2t^2)^2\) (ft on \(k\) value and also in (b): 1st two lines.) B1✓ [1]
(ii)(b) \(G_Y'(t) = \frac{1}{50}(5t^{-1} + 3 + 2t^2)(-5t^{-2} + 4t)\) M1A1
\(E(Y) = G_Y''(1) = -\frac{10}{50} = -\frac{1}{5}\) B1
\(G_Y''(t) = \frac{1}{50}\{(-5t^{-2} + 4t)^2 + (5t^{-1} + 3 + 2t^2)(10t^{-3} + 4)\}\) M1A1
\(G_Y''(1) = \frac{1}{50}(1 + 10 \times 14) = \frac{141}{50} = \sigma^2 + \frac{1}{25} + \frac{1}{5}\) A1B1
(B1 for their \(\sigma^2 + \mu^2 = \mu\).)
\(\Rightarrow \sigma^2 = \frac{129}{50} = 2.58\) (AWRT 2.58) A1 [8]
(i)(a) $k(5 + 3 + 2) = 1 \Rightarrow k = \frac{1}{10}$ **B1** [1]

(i)(b) Modal value is $-1$. **B1** [1]

(ii)(a) $G_Y(t) = \frac{1}{100}(5t^{-1} + 3 + 2t^2)^2$ (ft on $k$ value and also in (b): 1st two lines.) **B1**✓ [1]

(ii)(b) $G_Y'(t) = \frac{1}{50}(5t^{-1} + 3 + 2t^2)(-5t^{-2} + 4t)$ **M1A1**✓

$E(Y) = G_Y''(1) = -\frac{10}{50} = -\frac{1}{5}$ **B1**

$G_Y''(t) = \frac{1}{50}\{(-5t^{-2} + 4t)^2 + (5t^{-1} + 3 + 2t^2)(10t^{-3} + 4)\}$ **M1A1**✓

$G_Y''(1) = \frac{1}{50}(1 + 10 \times 14) = \frac{141}{50} = \sigma^2 + \frac{1}{25} + \frac{1}{5}$ **A1B1**

(B1 for their $\sigma^2 + \mu^2 = \mu$.)

$\Rightarrow \sigma^2 = \frac{129}{50} = 2.58$ (AWRT 2.58) **A1** [8]
5 The discrete random variable $X$ has probability generating function given by

$$\mathrm { G } _ { X } ( t ) = k \left( 5 t ^ { - 1 } + 3 + 2 t ^ { 2 } \right) ,$$

where $k$ is a constant.\\
(i) Find
\begin{enumerate}[label=(\alph*)]
\item the value of $k$,
\item the modal value of $X$.\\
(ii) The random variables $X _ { 1 }$ and $X _ { 2 }$ are independent observations of $X$.\\
(a) Write down the probability generating function of $Y$, where $Y = X _ { 1 } + X _ { 2 }$.\\
(b) Use your answer to part (ii)(a) to find $\mathrm { E } ( Y )$ and $\operatorname { Var } ( Y )$.
\end{enumerate}

\hfill \mbox{\textit{Pre-U Pre-U 9795/2 2013 Q5 [8]}}