Pre-U Pre-U 9795/1 2010 June — Question 5 8 marks

Exam BoardPre-U
ModulePre-U 9795/1 (Pre-U Further Mathematics Paper 1)
Year2010
SessionJune
Marks8
TopicCurve Sketching
TypeSketch rational with quadratic numerator
DifficultyStandard +0.8 This question requires algebraic division to identify the oblique asymptote, differentiation using the quotient rule, completing the square or sign analysis to prove the derivative inequality, and synthesizing multiple features (asymptotes, intercepts, monotonicity) into a coherent sketch. While the individual techniques are A-level standard, the proof requirement and the need to coordinate several analytical steps elevate this above routine curve sketching.
Spec1.02k Simplify rational expressions: factorising, cancelling, algebraic division1.02n Sketch curves: simple equations including polynomials1.07i Differentiate x^n: for rational n and sums

5 A curve has equation \(y = \frac { x ^ { 2 } + 5 x - 6 } { x + 3 }\) for \(x \neq - 3\).
  1. Show that \(\frac { \mathrm { d } y } { \mathrm {~d} x } > 1\) at all points on the curve.
  2. Sketch the curve, justifying all significant features.

(i)
\(\frac{dy}{dx} = \frac{(x+3)(2x+5)-(x^2+5x-6)\cdot 1}{(x+3)^2}\) M1 Use of quotient rule
\(= \frac{x^2+6x+21}{(x+3)^2} = 1 + \frac{12}{(x+3)^2} > 1\) M1 Division A1 Fully explained cso [3]
(ii) Vertical asymptote \(x = -3\) B1
Long-division: \(y = \frac{x^2+5x-6}{x+3} = x+2-\frac{12}{x+3}\) M1 This may happen first, then differentiation.
leading to oblique asymptote \(y = x+2\) A1
Factorising numerator: \(y = \frac{x^2+5x-6}{x+3} = \frac{(x+6)(x-1)}{x+3}\) M1
leading to \(y=0\), \(x=-6\), \(1\) A1
When \(x=0\), \(y=-2\) B1
Graph of curve: G1 No TPs
G1 All correct, ft provided sensible oblique asymptote [8]
**(i)**
$\frac{dy}{dx} = \frac{(x+3)(2x+5)-(x^2+5x-6)\cdot 1}{(x+3)^2}$ **M1** Use of quotient rule

$= \frac{x^2+6x+21}{(x+3)^2} = 1 + \frac{12}{(x+3)^2} > 1$ **M1** Division **A1** Fully explained **cso** [3]

**(ii)** Vertical asymptote $x = -3$ **B1**

Long-division: $y = \frac{x^2+5x-6}{x+3} = x+2-\frac{12}{x+3}$ **M1** This may happen first, then differentiation.

leading to oblique asymptote $y = x+2$ **A1**

Factorising numerator: $y = \frac{x^2+5x-6}{x+3} = \frac{(x+6)(x-1)}{x+3}$ **M1**

leading to $y=0$, $x=-6$, $1$ **A1**

When $x=0$, $y=-2$ **B1**

Graph of curve: **G1** No TPs

**G1** All correct, **ft** provided sensible oblique asymptote **[8]**
5 A curve has equation $y = \frac { x ^ { 2 } + 5 x - 6 } { x + 3 }$ for $x \neq - 3$.\\
(i) Show that $\frac { \mathrm { d } y } { \mathrm {~d} x } > 1$ at all points on the curve.\\
(ii) Sketch the curve, justifying all significant features.

\hfill \mbox{\textit{Pre-U Pre-U 9795/1 2010 Q5 [8]}}