CAIE FP1 2014 June — Question 1

Exam BoardCAIE
ModuleFP1 (Further Pure Mathematics 1)
Year2014
SessionJune
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TopicRoots of polynomials
1 The equation \(x ^ { 3 } + p x + q = 0\), where \(p\) and \(q\) are constants, with \(q \neq 0\), has one root which is the reciprocal of another root. Prove that \(p + q ^ { 2 } = 1\). 
1 The equation $x ^ { 3 } + p x + q = 0$, where $p$ and $q$ are constants, with $q \neq 0$, has one root which is the reciprocal of another root. Prove that $p + q ^ { 2 } = 1$.

\hfill \mbox{\textit{CAIE FP1 2014 Q1}}
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