CAIE P1 2005 June — Question 4 5 marks

Exam BoardCAIE
ModuleP1 (Pure Mathematics 1)
Year2005
SessionJune
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicBinomial Theorem (positive integer n)
TypeCoefficient zero after multiplying binomial
DifficultyModerate -0.3 Part (i) is straightforward binomial expansion requiring recall of the formula. Part (ii) requires identifying coefficients and solving a linear equation to make the x² term vanish—a standard technique but involves an extra conceptual step beyond pure recall, making it slightly easier than average overall.
Spec1.04a Binomial expansion: (a+b)^n for positive integer n

4
  1. Find the first 3 terms in the expansion of \(( 2 - x ) ^ { 6 }\) in ascending powers of \(x\).
  2. Find the value of \(k\) for which there is no term in \(x ^ { 2 }\) in the expansion of \(( 1 + k x ) ( 2 - x ) ^ { 6 }\).

AnswerMarks Guidance
(i) \((2 - x)^6 = 64 - 192x + 240x^2\)3 × B1 [3] One for each term. Allow \(2^6\).
(ii) \((1 + kx)(2 - x)^6\) coeff of \(x^2 = 240 - 192k = 0 \Rightarrow k = 5/4\) or \(1.25\)M1 A1 \(\checkmark\) [2] Must be considering sum of 2 terms. ft for his expansion. (allow M1 if looking for coeff of \(x\)).
(i) $(2 - x)^6 = 64 - 192x + 240x^2$ | 3 × B1 [3] | One for each term. Allow $2^6$.

(ii) $(1 + kx)(2 - x)^6$ coeff of $x^2 = 240 - 192k = 0 \Rightarrow k = 5/4$ or $1.25$ | M1 A1 $\checkmark$ [2] | Must be considering sum of 2 terms. ft for his expansion. (allow M1 if looking for coeff of $x$).
4 (i) Find the first 3 terms in the expansion of $( 2 - x ) ^ { 6 }$ in ascending powers of $x$.\\
(ii) Find the value of $k$ for which there is no term in $x ^ { 2 }$ in the expansion of $( 1 + k x ) ( 2 - x ) ^ { 6 }$.

\hfill \mbox{\textit{CAIE P1 2005 Q4 [5]}}