CAIE P1 2005 June — Question 1 4 marks

Exam BoardCAIE
ModuleP1 (Pure Mathematics 1)
Year2005
SessionJune
Marks4
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicStandard Integrals and Reverse Chain Rule
TypeFind curve equation from derivative (straightforward integration + point)
DifficultyEasy -1.3 This is a straightforward integration question requiring only direct application of the power rule and use of a boundary condition to find the constant. It's simpler than average A-level questions as it involves no chain rule, substitution, or problem-solving—just routine integration and substitution of a point.
Spec1.08a Fundamental theorem of calculus: integration as reverse of differentiation1.08b Integrate x^n: where n != -1 and sums

1 A curve is such that \(\frac { \mathrm { d } y } { \mathrm {~d} x } = 2 x ^ { 2 } - 5\). Given that the point \(( 3,8 )\) lies on the curve, find the equation of the curve.

AnswerMarks Guidance
\(y = \frac{2x^3}{3} - 5x\) \((+c)\)M1 A1 Attempt at integration. CAO
\((3,8)\) fits: \(y = \frac{2x^3}{3} - 5x + 5\)DM1 A1 [4] Uses \((3,8)\) in an integrated expression. CAO
$y = \frac{2x^3}{3} - 5x$ $(+c)$ | M1 A1 | Attempt at integration. CAO

$(3,8)$ fits: $y = \frac{2x^3}{3} - 5x + 5$ | DM1 A1 [4] | Uses $(3,8)$ in an integrated expression. CAO
1 A curve is such that $\frac { \mathrm { d } y } { \mathrm {~d} x } = 2 x ^ { 2 } - 5$. Given that the point $( 3,8 )$ lies on the curve, find the equation of the curve.

\hfill \mbox{\textit{CAIE P1 2005 Q1 [4]}}