| Exam Board | OCR |
|---|---|
| Module | FS1 AS (Further Statistics 1 AS) |
| Year | 2021 |
| Session | June |
| Marks | 7 |
| Topic | Geometric Distribution |
| Type | Non-geometric distribution identification |
| Difficulty | Standard +0.3 This is a straightforward combinatorics problem requiring basic permutation counting. Part (a) uses the 'treat as a block' technique, and part (b) uses the 'gaps method' - both are standard textbook exercises in Further Statistics 1. The calculations are mechanical once the approach is identified, making this slightly easier than average. |
| Spec | 5.01a Permutations and combinations: evaluate probabilities5.01b Selection/arrangement: probability problems |
2 The members of a team stand in a random order in a straight line for a photograph. There are four men and six women.
\begin{enumerate}[label=(\alph*)]
\item Find the probability that all the men are next to each other.
\item Find the probability that no two men are next to one another.
\end{enumerate}
\hfill \mbox{\textit{OCR FS1 AS 2021 Q2 [7]}}