OCR FP1 AS 2021 June — Question 4 8 marks

Exam BoardOCR
ModuleFP1 AS (Further Pure 1 AS)
Year2021
SessionJune
Marks8
TopicComplex Numbers Argand & Loci
TypeIntersection of two loci
DifficultyStandard +0.8 This FP1 question requires understanding two distinct loci (perpendicular bisector and half-line), finding their intersection algebraically by solving simultaneous equations involving complex numbers, and interpreting a degenerate case. While systematic, it demands solid technique across multiple complex number concepts and careful algebraic manipulation, placing it moderately above average difficulty.
Spec4.02k Argand diagrams: geometric interpretation4.02o Loci in Argand diagram: circles, half-lines

4 Two loci, \(C _ { 1 }\) and \(C _ { 2 }\), are defined by $$\begin{aligned} & C _ { 1 } = \left\{ z : | z | = \left| z - 4 d ^ { 2 } - 36 \right| \right\} \\ & C _ { 2 } = \left\{ z : \arg ( z - 12 d - 3 \mathrm { i } ) = \frac { 1 } { 4 } \pi \right\} \end{aligned}$$ where \(d\) is a real number.
  1. Find, in terms of \(d\), the complex number which is represented on an Argand diagram by the point of intersection of \(C _ { 1 }\) and \(C _ { 2 }\).
    [0pt] [You may assume that \(C _ { 1 } \cap C _ { 2 } \neq \varnothing\).]
  2. Explain why the solution found in part (a) is not valid when \(d = 3\).

4 Two loci, $C _ { 1 }$ and $C _ { 2 }$, are defined by

$$\begin{aligned}
& C _ { 1 } = \left\{ z : | z | = \left| z - 4 d ^ { 2 } - 36 \right| \right\} \\
& C _ { 2 } = \left\{ z : \arg ( z - 12 d - 3 \mathrm { i } ) = \frac { 1 } { 4 } \pi \right\}
\end{aligned}$$

where $d$ is a real number.
\begin{enumerate}[label=(\alph*)]
\item Find, in terms of $d$, the complex number which is represented on an Argand diagram by the point of intersection of $C _ { 1 }$ and $C _ { 2 }$.\\[0pt]
[You may assume that $C _ { 1 } \cap C _ { 2 } \neq \varnothing$.]
\item Explain why the solution found in part (a) is not valid when $d = 3$.
\end{enumerate}

\hfill \mbox{\textit{OCR FP1 AS 2021 Q4 [8]}}