AQA Further Paper 3 Mechanics 2023 June — Question 2 1 marks

Exam BoardAQA
ModuleFurther Paper 3 Mechanics (Further Paper 3 Mechanics)
Year2023
SessionJune
Marks1
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicMoments
TypeThree-dimensional force systems: finding resultant and couple
DifficultyModerate -0.5 This is a straightforward 2D moment calculation requiring the formula M = Fd or the cross product r × F. While it's a Further Maths mechanics question, it's a 1-mark multiple choice problem testing basic recall of moment calculation about a point, making it easier than the average A-level question despite being from a Further Maths paper.
Spec3.04a Calculate moments: about a point

2 The force \(( 3 \mathbf { i } + 4 \mathbf { j } ) \mathrm { N }\) acts at the point with coordinates \(( 0,2 )\) The unit vectors \(\mathbf { i }\) and \(\mathbf { j }\) are directed along the \(x\)-axis and the \(y\)-axis respectively.
Calculate the magnitude of the moment of this force about the origin.
Circle your answer.
[0pt] [1 mark]
6 Nm
8 Nm
10 Nm
14 Nm

Question 2:
AnswerMarks Guidance
AnswerMark Guidance
\(6 \text{ N m}\)B1 Circles correct answer
## Question 2:
| Answer | Mark | Guidance |
|--------|------|----------|
| $6 \text{ N m}$ | B1 | Circles correct answer |

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2 The force $( 3 \mathbf { i } + 4 \mathbf { j } ) \mathrm { N }$ acts at the point with coordinates $( 0,2 )$\\
The unit vectors $\mathbf { i }$ and $\mathbf { j }$ are directed along the $x$-axis and the $y$-axis respectively.\\
Calculate the magnitude of the moment of this force about the origin.\\
Circle your answer.\\[0pt]
[1 mark]\\
6 Nm\\
8 Nm\\
10 Nm\\
14 Nm

\hfill \mbox{\textit{AQA Further Paper 3 Mechanics 2023 Q2 [1]}}