AQA Further Paper 3 Mechanics 2019 June — Question 1 1 marks

Exam BoardAQA
ModuleFurther Paper 3 Mechanics (Further Paper 3 Mechanics)
Year2019
SessionJune
Marks1
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicHooke's law and elastic energy
TypeElastic potential energy calculations
DifficultyModerate -0.8 This is a direct application of the elastic potential energy formula EPE = λx²/(2l), requiring only substitution of given values (λ=55N, x=0.08m, l=0.4m) with no problem-solving or conceptual challenge. Being multiple choice with the answer provided makes it easier than average, though it's Further Maths content.
Spec6.02h Elastic PE: 1/2 k x^2

1 A spring has natural length 0.4 metres and modulus of elasticity 55 N
Calculate the elastic potential energy stored in the spring when the extension of the spring is 0.08 metres. Circle your answer. \(0.176 \mathrm {~J} \quad 0.44 \mathrm {~J} \quad 0.88 \mathrm {~J} \quad 1.76 \mathrm {~J}\)

Question 1:
AnswerMarks Guidance
AnswerMarks Guidance
\(0.44 \text{ J}\)B1 Circles correct answer
Total: 1
## Question 1:

| Answer | Marks | Guidance |
|--------|-------|----------|
| $0.44 \text{ J}$ | B1 | Circles correct answer |
| **Total: 1** | | |

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1 A spring has natural length 0.4 metres and modulus of elasticity 55 N\\
Calculate the elastic potential energy stored in the spring when the extension of the spring is 0.08 metres.

Circle your answer.\\
$0.176 \mathrm {~J} \quad 0.44 \mathrm {~J} \quad 0.88 \mathrm {~J} \quad 1.76 \mathrm {~J}$

\hfill \mbox{\textit{AQA Further Paper 3 Mechanics 2019 Q1 [1]}}