2 The random variable \(X\) has probability density function
$$f ( x ) = \begin{cases} 1 & 0 < x \leq \frac { 1 } { 2 } \\ \frac { 3 } { 8 } x ^ { - 2 } & \frac { 1 } { 2 } < x \leq \frac { 3 } { 2 } \\ 0 & \text { otherwise } \end{cases}$$
Find \(\mathrm { P } ( X < 1 )\)
Circle your answer.
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Question 2:
Answer Marks
Guidance
Answer Marks
Guidance
\(\dfrac{7}{8}\) B1 (AO1.1b)
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Total: 1
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## Question 2:
| Answer | Marks | Guidance |
|--------|-------|----------|
| $\dfrac{7}{8}$ | B1 (AO1.1b) | Circles correct answer |
| **Total: 1** | | |
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2 The random variable $X$ has probability density function
$$f ( x ) = \begin{cases} 1 & 0 < x \leq \frac { 1 } { 2 } \\ \frac { 3 } { 8 } x ^ { - 2 } & \frac { 1 } { 2 } < x \leq \frac { 3 } { 2 } \\ 0 & \text { otherwise } \end{cases}$$
Find $\mathrm { P } ( X < 1 )$
Circle your answer.\\[0pt]
[1 mark]\\
$\frac { 1 } { 8 }$\\
$\frac { 3 } { 8 }$\\
$\frac { 5 } { 8 }$\\
$\frac { 7 } { 8 }$\\
\includegraphics[max width=\textwidth, alt={}, center]{62cee897-6eac-40b3-84c1-a0d165ba6903-03_2488_1718_219_153}
\hfill \mbox{\textit{AQA Further Paper 3 Statistics 2022 Q2 [1]}}