CAIE M1 2017 June — Question 1 3 marks

Exam BoardCAIE
ModuleM1 (Mechanics 1)
Year2017
SessionJune
Marks3
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicWork done and energy
TypeWork done against air resistance - vertical motion
DifficultyModerate -0.8 This is a straightforward application of the work-energy principle requiring only two steps: calculate initial gravitational PE (mgh = 0.6×10×8 = 48J), calculate final KE (½mv² = 0.5×0.6×100 = 30J), then find the difference (18J). The question directly provides all needed values and requires only standard formula recall with no problem-solving insight or conceptual difficulty.
Spec6.02a Work done: concept and definition6.02d Mechanical energy: KE and PE concepts

1 A particle of mass 0.6 kg is dropped from a height of 8 m above the ground. The speed of the particle at the instant before hitting the ground is \(10 \mathrm {~m} \mathrm {~s} ^ { - 1 }\). Find the work done against air resistance.

Question 1:
AnswerMarks Guidance
AnswerMark Guidance
PE loss \(= 0.6 \times 10 \times 8 = 48\) JB1
KE gain \(= \frac{1}{2}(0.6)(10)^2 = 30\) JB1
WD against Res \(= 48 - 30 = 18\) JB1
Total: 3
## Question 1:

| Answer | Mark | Guidance |
|--------|------|----------|
| PE loss $= 0.6 \times 10 \times 8 = 48$ J | B1 | |
| KE gain $= \frac{1}{2}(0.6)(10)^2 = 30$ J | B1 | |
| WD against Res $= 48 - 30 = 18$ J | B1 | |
| **Total: 3** | | |

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1 A particle of mass 0.6 kg is dropped from a height of 8 m above the ground. The speed of the particle at the instant before hitting the ground is $10 \mathrm {~m} \mathrm {~s} ^ { - 1 }$. Find the work done against air resistance.\\

\hfill \mbox{\textit{CAIE M1 2017 Q1 [3]}}