Edexcel AS Paper 2 2018 June — Question 6 4 marks

Exam BoardEdexcel
ModuleAS Paper 2 (AS Paper 2)
Year2018
SessionJune
Marks4
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicSUVAT in 2D & Gravity
TypeVertical projection: time to ground
DifficultyModerate -0.8 This is a straightforward SUVAT application with standard values given. Students need only substitute into s = ut + ½at² and solve the resulting quadratic equation—a routine mechanics exercise requiring no problem-solving insight, making it easier than average.
Spec3.02d Constant acceleration: SUVAT formulae3.02h Motion under gravity: vector form

  1. A man throws a tennis ball into the air so that, at the instant when the ball leaves his hand, the ball is 2 m above the ground and is moving vertically upwards with speed \(9 \mathrm {~m} \mathrm {~s} ^ { - 1 }\)
The motion of the ball is modelled as that of a particle moving freely under gravity and the acceleration due to gravity is modelled as being of constant magnitude \(10 \mathrm {~m} \mathrm {~s} ^ { - 2 }\) The ball hits the ground \(T\) seconds after leaving the man's hand.
Using the model, find the value of \(T\).

Question 6:
AnswerMarks Guidance
Answer/WorkingMarks Guidance
Equation in \(t\) onlyM1 Complete method; correct no. of terms; condone sign errors; \(g\) need not be substituted
\(-2 = 9t - \frac{1}{2} \times 10t^2\)A1 Correct equation or correct equations; \(g=10\) must be substituted
\(5t^2 - 9t - 2 = 0 = (5t+1)(t-2)\)DM1 Dependent on first M1; for solving 3-term quadratic to find \(T\)
\(T=2\) (only)A1 \(T=2\) only (A0 if two times given)
# Question 6:
| Answer/Working | Marks | Guidance |
|---|---|---|
| Equation in $t$ only | M1 | Complete method; correct no. of terms; condone sign errors; $g$ need not be substituted |
| $-2 = 9t - \frac{1}{2} \times 10t^2$ | A1 | Correct equation or correct equations; $g=10$ must be substituted |
| $5t^2 - 9t - 2 = 0 = (5t+1)(t-2)$ | DM1 | Dependent on first M1; for solving 3-term quadratic to find $T$ |
| $T=2$ (only) | A1 | $T=2$ only (A0 if two times given) |

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\begin{enumerate}
  \item A man throws a tennis ball into the air so that, at the instant when the ball leaves his hand, the ball is 2 m above the ground and is moving vertically upwards with speed $9 \mathrm {~m} \mathrm {~s} ^ { - 1 }$
\end{enumerate}

The motion of the ball is modelled as that of a particle moving freely under gravity and the acceleration due to gravity is modelled as being of constant magnitude $10 \mathrm {~m} \mathrm {~s} ^ { - 2 }$

The ball hits the ground $T$ seconds after leaving the man's hand.\\
Using the model, find the value of $T$.

\hfill \mbox{\textit{Edexcel AS Paper 2 2018 Q6 [4]}}