| Exam Board | AQA |
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| Module | AS Paper 2 (AS Paper 2) |
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| Year | 2023 |
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| Session | June |
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| Topic | Reciprocal Trig & Identities |
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5 It is given that \(\sin 15 ^ { \circ } = \frac { \sqrt { 6 } - \sqrt { 2 } } { 4 }\) and \(\cos 15 ^ { \circ } = \frac { \sqrt { 6 } + \sqrt { 2 } } { 4 }\)
Use these two expressions to show that \(\tan 15 ^ { \circ } = 2 - \sqrt { 3 }\)
Fully justify your answer.