CAIE P1 2003 June — Question 6 5 marks

Exam BoardCAIE
ModuleP1 (Pure Mathematics 1)
Year2003
SessionJune
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicTrig Graphs & Exact Values
TypeSketch trig curve and straight line, count intersections
DifficultyModerate -0.3 This question involves sketching a standard sine curve with amplitude 3, finding a gradient through a known maximum point (straightforward calculation k=6/π), and using symmetry to identify the intersection at (-π/2, -3). While multi-part, each step uses routine techniques with no novel problem-solving required, making it slightly easier than average.
Spec1.02m Graphs of functions: difference between plotting and sketching1.02q Use intersection points: of graphs to solve equations1.05f Trigonometric function graphs: symmetries and periodicities

6
  1. Sketch the graph of the curve \(y = 3 \sin x\), for \(- \pi \leqslant x \leqslant \pi\). The straight line \(y = k x\), where \(k\) is a constant, passes through the maximum point of this curve for \(- \pi \leqslant x \leqslant \pi\).
  2. Find the value of \(k\) in terms of \(\pi\).
  3. State the coordinates of the other point, apart from the origin, where the line and the curve intersect.

AnswerMarks Guidance
(i) [Graph showing complete cycle with curves, not lines, -3 to +3 shown or implied, from \(-\pi\) to \(\pi\). Degrees ok]B2, 1 [2] For complete cycle, shape including curves, not lines, -3 to +3 shown or implied, for \(-\pi\) to \(\pi\). Degrees ok
(ii) \(x = \pi/2\), \(y = 3\) (allow if 90°) \(\rightarrow k = 6/\pi\) co.M1, A1 [2] Realising maximum is \((\pi/2, 3)\) + sub. Co (even if no graph)
(iii) \((-\pi/2, -3)\) – must be radiansB1 [1] Co (could come from incorrect graph)
**(i)** [Graph showing complete cycle with curves, not lines, -3 to +3 shown or implied, from $-\pi$ to $\pi$. Degrees ok] | B2, 1 [2] | For complete cycle, shape including curves, not lines, -3 to +3 shown or implied, for $-\pi$ to $\pi$. Degrees ok

**(ii)** $x = \pi/2$, $y = 3$ (allow if 90°) $\rightarrow k = 6/\pi$ co. | M1, A1 [2] | Realising maximum is $(\pi/2, 3)$ + sub. Co (even if no graph)

**(iii)** $(-\pi/2, -3)$ – must be radians | B1 [1] | Co (could come from incorrect graph)
6 (i) Sketch the graph of the curve $y = 3 \sin x$, for $- \pi \leqslant x \leqslant \pi$.

The straight line $y = k x$, where $k$ is a constant, passes through the maximum point of this curve for $- \pi \leqslant x \leqslant \pi$.\\
(ii) Find the value of $k$ in terms of $\pi$.\\
(iii) State the coordinates of the other point, apart from the origin, where the line and the curve intersect.

\hfill \mbox{\textit{CAIE P1 2003 Q6 [5]}}