CAIE P1 2003 June — Question 4 5 marks

Exam BoardCAIE
ModuleP1 (Pure Mathematics 1)
Year2003
SessionJune
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicArithmetic Sequences and Series
TypeSum of first n terms
DifficultyModerate -0.5 This is a straightforward application of arithmetic progression formulas requiring students to find the common difference from given terms, then determine the number of terms, and finally calculate the sum. While it involves multiple steps, each step uses standard AP formulas with no conceptual difficulty or problem-solving insight required, making it slightly easier than average.
Spec1.04h Arithmetic sequences: nth term and sum formulae

4 In an arithmetic progression, the 1 st term is - 10 , the 15th term is 11 and the last term is 41 . Find the sum of all the terms in the progression.

AnswerMarks Guidance
\(a = -10\); \(a + 14d = 11\); \(d = \frac{3}{2}\)M1, M1, A1 [3] Using \(a = (n-1)d\). Correct method – not for \(a + nd\). Co
\(a + (n-1)d = 41\); \(n = 35\)M1, A1 [2] Correct method – not for \(a + nd\). Co
Either \(S_n = n/2(2a + (n-1)d)\) or \(n/2(a + l) = 542.5\)M1, M1, A1 [5] Either of these used correctly. For his d and any n
$a = -10$; $a + 14d = 11$; $d = \frac{3}{2}$ | M1, M1, A1 [3] | Using $a = (n-1)d$. Correct method – not for $a + nd$. Co

$a + (n-1)d = 41$; $n = 35$ | M1, A1 [2] | Correct method – not for $a + nd$. Co

Either $S_n = n/2(2a + (n-1)d)$ or $n/2(a + l) = 542.5$ | M1, M1, A1 [5] | Either of these used correctly. For his d and any n
4 In an arithmetic progression, the 1 st term is - 10 , the 15th term is 11 and the last term is 41 . Find the sum of all the terms in the progression.

\hfill \mbox{\textit{CAIE P1 2003 Q4 [5]}}