AQA FP1 2010 January — Question 4 7 marks

Exam BoardAQA
ModuleFP1 (Further Pure Mathematics 1)
Year2010
SessionJanuary
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicMatrices
TypeMatrix satisfying given equation
DifficultyStandard +0.3 This is a straightforward Further Maths matrix algebra question requiring routine computation of (A-I)², recognizing it equals a scalar multiple of I, then solving a simple equation by comparing matrices. The steps are mechanical with no conceptual difficulty beyond basic matrix operations, making it slightly easier than average even for FP1.
Spec4.03a Matrix language: terminology and notation4.03b Matrix operations: addition, multiplication, scalar

4 It is given that $$\mathbf { A } = \left[ \begin{array} { l l } 1 & 4 \\ 3 & 1 \end{array} \right]$$ and that \(\mathbf { I }\) is the \(2 \times 2\) identity matrix.
  1. Show that \(( \mathbf { A } - \mathbf { I } ) ^ { 2 } = k \mathbf { I }\) for some integer \(k\).
  2. Given further that $$\mathbf { B } = \left[ \begin{array} { l l } 1 & 3 \\ p & 1 \end{array} \right]$$ find the integer \(p\) such that $$( \mathbf { A } - \mathbf { B } ) ^ { 2 } = ( \mathbf { A } - \mathbf { I } ) ^ { 2 }$$

AnswerMarks Guidance
4(a)\(I = \begin{bmatrix} 1 & 0 \\ 0 & 1 \end{bmatrix}\) B1
Attempt at \((A - I)^2\)M1 with at most one numerical error
\((A - I)^2 = \begin{bmatrix} 0 & 4 \\ 3 & 0 \end{bmatrix}\begin{bmatrix} 0 & 4 \\ 3 & 0 \end{bmatrix} = 12I\)A1 3 marks
4(b)\(A - B = \begin{bmatrix} 0 & 1 \\ 3 - p & 0 \end{bmatrix}\) B1
\((A - B)^2 = \begin{bmatrix} 3 - p & 0 \\ 0 & 3 - p \end{bmatrix}\)M1A1 M1 A0 if 3 entries correct
\(... = (A - I)^2\) for \(p = -9\)A1F ft wrong value of \(k\)
4 marks
Total for Q47 marks
4(a) | $I = \begin{bmatrix} 1 & 0 \\ 0 & 1 \end{bmatrix}$ | B1 | stated or used at any stage |
| Attempt at $(A - I)^2$ | M1 | with at most one numerical error |
| $(A - I)^2 = \begin{bmatrix} 0 & 4 \\ 3 & 0 \end{bmatrix}\begin{bmatrix} 0 & 4 \\ 3 & 0 \end{bmatrix} = 12I$ | A1 | 3 marks |

4(b) | $A - B = \begin{bmatrix} 0 & 1 \\ 3 - p & 0 \end{bmatrix}$ | B1 |
| $(A - B)^2 = \begin{bmatrix} 3 - p & 0 \\ 0 & 3 - p \end{bmatrix}$ | M1A1 | M1 A0 if 3 entries correct |
| $... = (A - I)^2$ for $p = -9$ | A1F | ft wrong value of $k$ |
| | | 4 marks |

| **Total for Q4** | **7 marks** |

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4 It is given that

$$\mathbf { A } = \left[ \begin{array} { l l } 
1 & 4 \\
3 & 1
\end{array} \right]$$

and that $\mathbf { I }$ is the $2 \times 2$ identity matrix.
\begin{enumerate}[label=(\alph*)]
\item Show that $( \mathbf { A } - \mathbf { I } ) ^ { 2 } = k \mathbf { I }$ for some integer $k$.
\item Given further that

$$\mathbf { B } = \left[ \begin{array} { l l } 
1 & 3 \\
p & 1
\end{array} \right]$$

find the integer $p$ such that

$$( \mathbf { A } - \mathbf { B } ) ^ { 2 } = ( \mathbf { A } - \mathbf { I } ) ^ { 2 }$$
\end{enumerate}

\hfill \mbox{\textit{AQA FP1 2010 Q4 [7]}}