AQA M1 2006 January — Question 2 5 marks

Exam BoardAQA
ModuleM1 (Mechanics 1)
Year2006
SessionJanuary
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicVariable acceleration (1D)
TypeVector motion with components
DifficultyModerate -0.8 This is a straightforward integration question requiring students to integrate constant acceleration vectors and apply initial conditions. The calculation is routine (integrate -3i + 12j, add constant 4i, then find magnitude at t=0.5) with no conceptual challenges beyond basic mechanics definitions. Easier than average A-level due to minimal steps and standard technique.
Spec1.10h Vectors in kinematics: uniform acceleration in vector form3.02f Non-uniform acceleration: using differentiation and integration3.02g Two-dimensional variable acceleration

2 A particle \(P\) moves with acceleration \(( - 3 \mathbf { i } + 12 \mathbf { j } ) \mathrm { m } \mathrm { s } ^ { - 2 }\). Initially the velocity of \(P\) is \(4 \mathbf { i } \mathrm {~m} \mathrm {~s} ^ { - 1 }\).
  1. Find the velocity of \(P\) at time \(t\) seconds.
  2. Find the speed of \(P\) when \(t = 0.5\).

Question 2:
Part (a)
AnswerMarks Guidance
WorkingMarks Guidance
\(\mathbf{v} = 4\mathbf{i} + (-3\mathbf{i} + 12\mathbf{j})t\)M1, A1 Total: 2
Part (b)
AnswerMarks Guidance
WorkingMarks Guidance
\(t = 0.5\), \(\mathbf{v} = 2.5\mathbf{i} + 6\mathbf{j}\)B1\(\sqrt{}\) \(\sqrt{}\) 2 terms and \(t\) substituted
\(\text{Speed} = \sqrt{2.5^2 + 6^2}\)M1 2 terms
\(\text{Speed} = 6.5 \text{ ms}^{-1}\)A1\(\sqrt{}\) Total: 3
## Question 2:

### Part (a)
| Working | Marks | Guidance |
|---------|-------|----------|
| $\mathbf{v} = 4\mathbf{i} + (-3\mathbf{i} + 12\mathbf{j})t$ | M1, A1 | Total: 2 | use of $\mathbf{v} = \mathbf{u} + \mathbf{a}t$ |

### Part (b)
| Working | Marks | Guidance |
|---------|-------|----------|
| $t = 0.5$, $\mathbf{v} = 2.5\mathbf{i} + 6\mathbf{j}$ | B1$\sqrt{}$ | $\sqrt{}$ 2 terms and $t$ substituted |
| $\text{Speed} = \sqrt{2.5^2 + 6^2}$ | M1 | 2 terms |
| $\text{Speed} = 6.5 \text{ ms}^{-1}$ | A1$\sqrt{}$ | Total: 3 | $\sqrt{}$ 2 terms |

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2 A particle $P$ moves with acceleration $( - 3 \mathbf { i } + 12 \mathbf { j } ) \mathrm { m } \mathrm { s } ^ { - 2 }$. Initially the velocity of $P$ is $4 \mathbf { i } \mathrm {~m} \mathrm {~s} ^ { - 1 }$.
\begin{enumerate}[label=(\alph*)]
\item Find the velocity of $P$ at time $t$ seconds.
\item Find the speed of $P$ when $t = 0.5$.
\end{enumerate}

\hfill \mbox{\textit{AQA M1 2006 Q2 [5]}}